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Geographic coordinate conversion
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====Orthogonality==== The [[Orthogonal coordinates|orthogonality]] of the coordinates is confirmed via differentiation: :<math>\begin{align} \begin{pmatrix} dX \\ dY \\ dZ \end{pmatrix} &= \begin{pmatrix} -\sin\lambda & -\sin\phi \cos\lambda & \cos\phi \cos\lambda \\ \cos\lambda & -\sin\phi \sin\lambda & \cos\phi \sin\lambda \\ 0 & \cos\phi & \sin\phi \\ \end{pmatrix} \begin{pmatrix} dE \\ dN \\ dU \end{pmatrix}, \\[3pt] \begin{pmatrix} dE \\ dN \\ dU \end{pmatrix} &= \begin{pmatrix} \left(N(\phi) + h\right) \cos\phi & 0 & 0 \\ 0 & M(\phi) + h & 0 \\ 0 & 0 & 1 \\ \end{pmatrix} \begin{pmatrix} d\lambda \\ d\phi \\ dh \end{pmatrix}, \end{align}</math> <!-- : <math>\begin{align} & \big(dX,\, dY,\, dZ\big) \\[6pt] = & \big(-\sin\phi \cos\lambda,\, -\sin\phi \sin\lambda,\, \cos\phi\big) \left(M(\phi) + h\right)\, d\phi \\[6pt] &{}+ \big(-\sin\lambda,\, \cos\lambda,\, 0\big)\left(N(\phi) + h\right) \cos\phi\, d\lambda \\[6pt] &{}+ \big(\cos\lambda \cos\phi,\, \cos\phi \sin\lambda,\, \sin\phi\big)\, dh, \end{align}</math> --> where :<math> M(\phi) = \frac{a\left(1 - e^2\right)}{\left(1 - e^2 \sin^2 \phi\right)^\frac{3}{2}} = N(\phi) \frac{1 - e^2}{1 - e^2\sin^2\phi} </math> (see also "[[Meridian arc#Definition|Meridian arc on the ellipsoid]]"). <!-- The infinitesimal length caused by latitude and longitude is calculated as follows (see also "[[Meridian arc#Meridian distance on the ellipsoid|Meridian arc on the ellipsoid]]"): : <math> ds^2 = \left(\frac{a\left(1 - e^2\right)}{\left(1 - e^2 \sin^2\phi\right)^\frac{3}{2}} + h\right)^2 d\phi^2 + \left(\frac{a}{\sqrt{1 - e^2 \sin^2\phi}} + h\right)^2 \cos^2\phi\, d\lambda^2 . </math> -->
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