Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Modular form
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
=== Standard definition === A modular form of weight <math>k</math> for the [[modular group]] :<math>\text{SL}(2, \Z) = \left \{ \left. \begin{pmatrix}a & b \\ c & d \end{pmatrix} \right | a, b, c, d \in \Z,\ ad-bc = 1 \right \}</math> is a function <math>f</math> on the [[upper half-plane]] <math>\mathcal{H}=\{z\in\C\mid \operatorname{Im}(z)>0\}</math> satisfying the following three conditions: # <math>f</math> is [[holomorphic function|holomorphic]] on <math>\mathcal{H}</math>. # For any <math>z\in\mathcal{H}</math> and any matrix in <math>\text{SL}(2, \Z)</math>, we have #:<math> f\left(\frac{az+b}{cz+d}\right) = (cz+d)^k f(z)</math>. # <math>f</math> is bounded as <math>\operatorname{Im}(z)\to\infty</math>. Remarks: * The weight <math>k</math> is typically a positive integer. * For odd <math>k</math>, only the zero function can satisfy the second condition. * The third condition is also phrased by saying that <math>f</math> is "holomorphic at the cusp", a terminology that is explained below. Explicitly, the condition means that there exist some <math> M, D > 0 </math> such that <math> \operatorname{Im}(z) > M \implies |f(z)| < D </math>, meaning <math>f</math> is bounded above some horizontal line. * The second condition for ::<math>S = \begin{pmatrix}0 & -1 \\ 1 & 0 \end{pmatrix}, \qquad T = \begin{pmatrix}1 & 1 \\ 0 & 1 \end{pmatrix}</math> :reads ::<math>f\left(-\frac{1}{z}\right) = z^k f(z), \qquad f(z + 1) = f(z)</math> :respectively. Since <math>S</math> and <math>T</math> [[generating set of a group|generate]] the group <math>\text{SL}(2, \Z)</math>, the second condition above is equivalent to these two equations. * Since <math>f(z+1)=f(z)</math>, modular forms are [[periodic function]]s with period {{math|1}}, and thus have a [[Fourier series]].
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)