Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Proton–proton chain
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
===The {{nowrap|p–p III}} branch=== [[File:Proton-Proton III chain reaction.svg|thumb|Proton–proton III chain]] <!-- Autogenerated using Phykiformulae 0.11 by [[User:SkyLined]] He-3 + He-4 → Be-7 + y Be-7 + H → B-8 + y B-8 _ _ → Be-8 + e+ + ve Be-8 _ _ → 2He -->:{| border="0" |- style="height:2em;" |{{nuclide|link=yes|helium|3}} ||+ ||{{nuclide|link=yes|helium|4}} ||→ ||{{nuclide|link=yes|beryllium|7}} ||+ ||{{math|{{SubatomicParticle|link=yes|Gamma}}}} || || ||+ ||{{val|1.59|u=MeV}} |- style="height:2em;" |{{nuclide|link=yes|beryllium|7}} ||+ ||{{nuclide|link=yes|hydrogen|1}} ||→ ||{{nuclide|link=yes|boron|8}} ||+ ||{{math|{{SubatomicParticle|link=|Gamma}}}} |- style="height:2em;" |{{nuclide|link=yes|boron|8}} || || ||→ ||{{nuclide|link=yes|beryllium|8}} ||+ ||{{SubatomicParticle|link=yes|Positron}} ||+ ||{{SubatomicParticle|link=yes|Electron Neutrino}} || |- style="height:2em;" |{{nuclide|link=yes|beryllium|8}} || || ||→ ||2 {{nuclide|link=yes|helium|4}} |} The last three stages of this chain, plus the positron annihilation, contribute a total of 18.209 MeV, though much of this is lost to the neutrino. The {{nowrap|p–p III}} chain is dominant if the temperature exceeds {{val|25|u=MK}}.<ref name=":1" /> The {{nowrap|p–p III}} chain is not a major source of energy in the Sun, but it was very important in the [[solar neutrino problem]] because it generates very high energy neutrinos (up to {{val|14.06|u=MeV}}).
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)