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Transconductance
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=== Field-effect transistors === Similarly, in [[field-effect transistor]]s, and [[MOSFET]]s in particular, transconductance is the change in the drain current divided by the small change in the gate–source voltage with a constant drain–source voltage. Typical values of {{math|''g''<sub>m</sub>}} for a small-signal field-effect transistor are {{val|1|to|30|u=mS}}. Using the [[Channel length modulation#Shichman–Hodges model|Shichman–Hodges model]], the transconductance for the MOSFET can be expressed as (see ''{{slink|MOSFET#Modes of operation}}'') : <math>g_\text{m} = \frac{2I_\text{D}}{V_\text{OV}},</math> where {{math|''I''<sub>D</sub>}} is the DC drain current at the [[bias point]], and {{math|''V''<sub>OV</sub>}} is the [[overdrive voltage]], which is the difference between the bias point gate–source voltage and the [[threshold voltage]] (i.e., {{math|1=''V''<sub>OV</sub> ≡ ''V''<sub>GS</sub> – ''V''<sub>th</sub>}}).<ref name=Sedra> {{citation |last1=Sedra |first1=A. S. |last2=Smith |first2=K. C. |title=Microelectronic Circuits |year=1998 |edition=Fourth |publisher=Oxford University Press |location=New York |isbn=0-19-511663-1 |url=http://worldcat.org/isbn/0-19-514251-9 }}</ref>{{rp|p. 395, Eq. (5.45)}} The overdrive voltage (sometimes known as the effective voltage) is customarily chosen at about 70–200 mV for the [[65 nm process]] node ({{nowrap|{{math|''I''<sub>D</sub>}} ≈ 1.13 mA/μm × width}}) for a {{math|''g''<sub>m</sub>}} of 11–32 mS/μm.<ref name=Baker> {{citation |last=Baker |first=R. Jacob |title=CMOS Circuit Design, Layout, and Simulation, Third Edition |year=2010 |publisher=Wiley-IEEE |location=New York |isbn=978-0-470-88132-3 |url=http://worldcat.org/isbn/978-0-470-88132-3 }}</ref>{{rp|p. 300, Table 9.2}}<ref name=Sansen> {{citation |last=Sansen |first=W. M. C. |title=Analog Design Essentials |year=2006 |publisher=Springer |location=Dordrecht |isbn=0-387-25746-2 |url=http://worldcat.org/isbn/0387257462 }}</ref>{{rp|p. 15, §0127}} Additionally, the transconductance for the junction FET is given by : <math>g_\text{m} = \frac{2I_\text{DSS}}{|V_\text{P}|} \left(1 - \frac{V_\text{GS}}{V_\text{P}}\right),</math> where {{math|''V''<sub>P</sub>}} is the pinchoff voltage, and {{math|''I''<sub>DSS</sub>}} is the maximum drain current.
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