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===Tuples as nested ordered pairs=== Another way of modeling tuples in set theory is as nested [[ordered pair]]s. This approach assumes that the notion of ordered pair has already been defined. # The 0-tuple (i.e. the empty tuple) is represented by the empty set <math>\emptyset</math>. # An {{math|''n''}}-tuple, with {{math|''n'' > 0}}, can be defined as an ordered pair of its first entry and an {{math|(''n'' β 1)}}-tuple (which contains the remaining entries when {{math|''n'' > 1)}}: #: <math>(a_1, a_2, a_3, \ldots, a_n) = (a_1, (a_2, a_3, \ldots, a_n))</math> This definition can be applied recursively to the {{math|(''n'' β 1)}}-tuple: : <math>(a_1, a_2, a_3, \ldots, a_n) = (a_1, (a_2, (a_3, (\ldots, (a_n, \emptyset)\ldots))))</math> Thus, for example: : <math> \begin{align} (1, 2, 3) & = (1, (2, (3, \emptyset))) \\ (1, 2, 3, 4) & = (1, (2, (3, (4, \emptyset)))) \\ \end{align} </math> A variant of this definition starts "peeling off" elements from the other end: # The 0-tuple is the empty set <math>\emptyset</math>. # For {{math|''n'' > 0}}: #: <math>(a_1, a_2, a_3, \ldots, a_n) = ((a_1, a_2, a_3, \ldots, a_{n-1}), a_n)</math> This definition can be applied recursively: : <math>(a_1, a_2, a_3, \ldots, a_n) = ((\ldots(((\emptyset, a_1), a_2), a_3), \ldots), a_n)</math> Thus, for example: : <math> \begin{align} (1, 2, 3) & = (((\emptyset, 1), 2), 3) \\ (1, 2, 3, 4) & = ((((\emptyset, 1), 2), 3), 4) \\ \end{align} </math>
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