Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Chain rule
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
=== Quotient rule === {{See also|Quotient rule}} The chain rule can be used to derive some well-known differentiation rules. For example, the quotient rule is a consequence of the chain rule and the [[product rule]]. To see this, write the function {{math|''f''(''x'')/''g''(''x'')}} as the product {{math|''f''(''x'') Β· 1/''g''(''x'')}}. First apply the product rule: <math display="block">\begin{align} \frac{d}{dx}\left(\frac{f(x)}{g(x)}\right) &= \frac{d}{dx}\left(f(x)\cdot\frac{1}{g(x)}\right) \\ &= f'(x)\cdot\frac{1}{g(x)} + f(x)\cdot\frac{d}{dx}\left(\frac{1}{g(x)}\right). \end{align}</math> To compute the derivative of {{math|1/''g''(''x'')}}, notice that it is the composite of {{mvar|g}} with the reciprocal function, that is, the function that sends {{mvar|x}} to {{math|1/''x''}}. The derivative of the reciprocal function is <math>-1/x^2\!</math>. By applying the chain rule, the last expression becomes: <math display="block">f'(x)\cdot\frac{1}{g(x)} + f(x)\cdot\left(-\frac{1}{g(x)^2}\cdot g'(x)\right) = \frac{f'(x) g(x) - f(x) g'(x)}{g(x)^2},</math> which is the usual formula for the quotient rule.
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)