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Uncertainty principle
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===Quantum harmonic oscillator stationary states=== {{Main article|Quantum harmonic oscillator|Stationary state}} Consider a one-dimensional quantum harmonic oscillator. It is possible to express the position and momentum operators in terms of the [[creation and annihilation operators]]: <math display="block">\hat x = \sqrt{\frac{\hbar}{2m\omega}}(a+a^\dagger)</math> <math display="block">\hat p = i\sqrt{\frac{m \omega\hbar}{2}}(a^\dagger-a).</math> Using the standard rules for creation and annihilation operators on the energy eigenstates, <math display="block">a^{\dagger}|n\rangle=\sqrt{n+1}|n+1\rangle</math> <math display="block">a|n\rangle=\sqrt{n}|n-1\rangle, </math> the variances may be computed directly, <math display="block">\sigma_x^2 = \frac{\hbar}{m\omega} \left( n+\frac{1}{2}\right)</math> <math display="block">\sigma_p^2 = \hbar m\omega \left( n+\frac{1}{2}\right)\, .</math> The product of these standard deviations is then <math display="block">\sigma_x \sigma_p = \hbar \left(n+\frac{1}{2}\right) \ge \frac{\hbar}{2}.~</math> In particular, the above Kennard bound<ref name="Kennard" /> is saturated for the [[ground state]] {{math|''n''{{=}}0}}, for which the probability density is just the [[normal distribution]].
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