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Gaussian gravitational constant
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===Gauss's original=== Gauss begins his ''Theoria Motus'' by presenting without proof several laws concerning the motion of bodies about the Sun.<ref name="Gauss"/> Later in the text, he mentions that [[Pierre-Simon Laplace]] treats these in detail in his ''Mécanique Céleste''.<ref>{{cite book | last1 = Laplace | first1 = Pierre Simon|last2 = Bowditch|first2 = Nathaniel | title = Mécanique Céleste | publisher = Hilliard, Gray, Little and Wilkins|location= Boston | year = 1829|url=https://archive.org/details/mcaniquecles01laplrich}}</ref> Gauss's final two laws are as follows: * The [[area]] swept by a line joining a body and the [[Sun]] divided by the time in which it is swept gives a constant [[quotient]]. This is [[Johannes Kepler|Kepler]]'s [[Kepler's laws of planetary motion#Second law|second law of planetary motion]]. * The [[Square (algebra)|square]] of this quotient is proportional to the parameter (that is, the [[Ellipse#Latus rectum|latus rectum]]) of the [[orbit]] and the [[addition|sum]] of the [[mass]] of the Sun and the body. This is a modified form of [[Kepler's laws of planetary motion#Third law|Kepler's third law]]. He next defines: *{{math|2''p''}} as the parameter (i.e., the [[latus rectum]]) of a body's orbit, *{{mvar|μ}} as the mass of the body, where the mass of the Sun = 1, *{{math|{{sfrac|1|2}}''g''}} as the area swept out by a line joining the Sun and the body, *{{mvar|t}} as the time in which this area is swept, and declares that :<math>\frac{g}{t\sqrt{p}\sqrt{1+\mu}}</math> is "constant for all heavenly bodies". He continues, "it is of no importance which body we use for determining this number," and hence uses Earth, defining *unit distance = Earth's mean distance (that is, its [[semi-major axis]]) from the Sun, *unit time = one solar [[day]]. He states that the area swept out by Earth in its orbit "will evidently be" {{math|π{{sqrt|''p''}}}}, and uses this to simplify his constant to :<math>\frac{2\pi}{t\sqrt{1+\mu}}.</math> Here, he names the constant {{mvar|k}} and plugging in some measured values, {{mvar|t}} = {{val|365.2563835}} days, {{mvar|μ}} = {{sfrac|1|{{val|354710}}}} solar masses, achieves the result {{math|''k''}} = {{val|0.01720209895}}.
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