Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Kolmogorov complexity
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
===A more formal treatment=== '''Theorem''': If ''K''<sub>1</sub> and ''K''<sub>2</sub> are the complexity functions relative to [[Turing complete]] description languages ''L''<sub>1</sub> and ''L''<sub>2</sub>, then there is a constant ''c'' β which depends only on the languages ''L''<sub>1</sub> and ''L''<sub>2</sub> chosen β such that :β''s''. β''c'' β€ ''K''<sub>1</sub>(''s'') β ''K''<sub>2</sub>(''s'') β€ ''c''. '''Proof''': By symmetry, it suffices to prove that there is some constant ''c'' such that for all strings ''s'' :''K''<sub>1</sub>(''s'') β€ ''K''<sub>2</sub>(''s'') + ''c''. Now, suppose there is a program in the language ''L''<sub>1</sub> which acts as an [[interpreter (computing)|interpreter]] for ''L''<sub>2</sub>: '''function''' InterpretLanguage('''string''' ''p'') where ''p'' is a program in ''L''<sub>2</sub>. The interpreter is characterized by the following property: : Running <code>InterpretLanguage</code> on input ''p'' returns the result of running ''p''. Thus, if '''P''' is a program in ''L''<sub>2</sub> which is a minimal description of ''s'', then <code>InterpretLanguage</code>('''P''') returns the string ''s''. The length of this description of ''s'' is the sum of # The length of the program <code>InterpretLanguage</code>, which we can take to be the constant ''c''. # The length of '''P''' which by definition is ''K''<sub>2</sub>(''s''). This proves the desired upper bound.
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)