Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Maximum modulus principle
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
===Using Cauchy's Integral Formula=== Source:<ref>{{cite book |last1=Conway |first1=John B. |editor1-last=Axler |editor1-first=S. |editor2-last=Gehring |editor2-first=F.W. |editor3-last=Ribet |editor3-first=K.A. |title=Functions of One Complex Variable I |date=1978 |publisher=Springer Science+Business Media, Inc. |location=New York |isbn=978-1-4612-6314-2 |edition=2}}</ref> As <math>D</math> is open, there exists <math>\overline{B}(a,r)</math> (a closed ball centered at <math>a \in D</math> with radius <math>r>0</math>) such that <math>\overline{B}(a,r) \subset D</math>. We then define the boundary of the closed ball with positive orientation as <math>\gamma(t)=a+re^{it}, t \in [0,2\pi]</math>. Invoking Cauchy's integral formula, we obtain :<math> 0 \leq \int_{0}^{2\pi} |f(a)|-| f(a+re^{it})| \,dt \leq 0 </math> For all <math>t \in [0,2\pi]</math>, <math>| f(a) |-| f(a+re^{it}) | \geq 0</math>, so <math>| f(a)|=| f(a+re^{it}) |</math>. This also holds for all balls of radius less than <math>r</math> centered at <math>a</math>. Therefore, <math>f(z)=f(a)</math> for all <math>z \in \overline{B}(a,r)</math>. Now consider the constant function <math>g(z)=f(a)</math> for all <math>z \in D</math>. Then one can construct a sequence of distinct points located in <math>\overline{B}(a,r)</math> where the holomorphic function <math>g-f</math> vanishes. As <math>\overline{B}(a,r)</math> is closed, the sequence converges to some point in <math>\overline{B}(a,r) \in D</math>. This means <math>f-g</math> vanishes everywhere in <math>D</math> which implies <math>f(z)=f(a)</math> for all <math>z \in D</math>.
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)