Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Riesz representation theorem
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
=== Observations === If <math>\varphi \in H^*</math> then <math display=block>\varphi \left(f_{\varphi}\right) = \left\langle f_{\varphi}, f_{\varphi} \right\rangle = \left\|f_{\varphi}\right\|^2 = \|\varphi\|^2.</math> So in particular, <math>\varphi \left(f_{\varphi}\right) \geq 0</math> is always real and furthermore, <math>\varphi \left(f_{\varphi}\right) = 0</math> if and only if <math>f_{\varphi} = 0</math> if and only if <math>\varphi = 0.</math> '''Linear functionals as affine hyperplanes''' A non-trivial continuous linear functional <math>\varphi</math> is often interpreted geometrically by identifying it with the affine hyperplane <math>A := \varphi^{-1}(1)</math> (the kernel <math>\ker\varphi = \varphi^{-1}(0)</math> is also often visualized alongside <math>A := \varphi^{-1}(1)</math> although knowing <math>A</math> is enough to reconstruct <math>\ker \varphi</math> because if <math>A = \varnothing</math> then <math>\ker \varphi = H</math> and otherwise <math>\ker \varphi = A - A</math>). In particular, the norm of <math>\varphi</math> should somehow be interpretable as the "norm of the hyperplane <math>A</math>". When <math>\varphi \neq 0</math> then the Riesz representation theorem provides such an interpretation of <math>\|\varphi\|</math> in terms of the affine hyperplane<ref group=note name="VectorSpaceStructureOnAffineHyperplanesInducedByDualSpace" /> <math>A := \varphi^{-1}(1)</math> as follows: using the notation from the theorem's statement, from <math>\|\varphi\|^2 \neq 0</math> it follows that <math>C := \varphi^{-1}\left(\|\varphi\|^2\right) = \|\varphi\|^2 \varphi^{-1}(1) = \|\varphi\|^2 A</math> and so <math>\|\varphi\| = \left\|f_{\varphi}\right\| = \inf_{c \in C} \|c\|</math> implies <math>\|\varphi\| = \inf_{a \in A} \|\varphi\|^2 \|a\|</math> and thus <math>\|\varphi\| = \frac{1}{\inf_{a \in A} \|a\|}.</math> This can also be seen by applying the [[Hilbert projection theorem]] to <math>A</math> and concluding that the global minimum point of the map <math>A \to [0, \infty)</math> defined by <math>a \mapsto \|a\|</math> is <math>\frac{f_{\varphi}}{\|\varphi\|^2} \in A.</math> The formulas <math display=block>\frac{1}{\inf_{a \in A} \|a\|} = \sup_{a \in A} \frac{1}{\|a\|}</math> provide the promised interpretation of the linear functional's norm <math>\|\varphi\|</math> entirely in terms of its associated affine hyperplane <math>A = \varphi^{-1}(1)</math> (because with this formula, knowing only the {{em|set}} <math>A</math> is enough to describe the norm of its associated linear {{em|functional}}). Defining <math>\frac{1}{\infty} := 0,</math> the [[infimum]] formula <math display=block>\|\varphi\| = \frac{1}{\inf_{a \in \varphi^{-1}(1)} \|a\|}</math> will also hold when <math>\varphi = 0.</math> When the supremum is taken in <math>\R</math> (as is typically assumed), then the supremum of the empty set is <math>\sup \varnothing = - \infty</math> but if the supremum is taken in the non-negative reals <math>[0, \infty)</math> (which is the [[Image of a function|image]]/range of the norm <math>\|\,\cdot\,\|</math> when <math>\dim H > 0</math>) then this supremum is instead <math>\sup \varnothing = 0,</math> in which case the supremum formula <math>\|\varphi\| = \sup_{a \in \varphi^{-1}(1)} \frac{1}{\|a\|}</math> will also hold when <math>\varphi = 0</math> (although the atypical equality <math>\sup \varnothing = 0</math> is usually unexpected and so risks causing confusion).
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)