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Trigonometric interpolation
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===Odd number of points=== Further simplification by using ({{EquationNote|4}}) would be an obvious approach, but is obviously involved. A much simpler approach is to consider the [[Dirichlet kernel]] :<math>D(x,N)=\frac{1}{N} +\frac{2}{N} \sum_{k=1}^{(N-1)/2}\cos(kx) = \frac{\sin\tfrac12 Nx}{N\sin\tfrac12 x},</math> where <math>N>0</math> is odd. It can easily be seen that <math>D(x,N)</math> is a linear combination of the right powers of <math>e^{ix}</math> and satisfies :<math>D(x_m,N)=\begin{cases}0\text{ for } m\neq0 \\1\text{ for } m=0\end{cases}.</math> Since these two properties uniquely define the coefficients <math>t_k(x)</math> in ({{EquationNote|5}}), it follows that :<math>\begin{align} t_k(x) &= D(x-x_k,N)=\begin{cases} \dfrac{\sin\tfrac12 N(x-x_k)}{N\sin\tfrac12 (x-x_k)} \text{ for } x\neq x_k\\[10mu] \lim\limits_{x\to 0} \dfrac{\sin\tfrac12 Nx}{N\sin\tfrac12 x}=1 \text{ for } x= x_k \end{cases}\\&= \frac{\mathrm{sinc}\,\tfrac12 N(x-x_k)}{\mathrm{sinc}\,\tfrac12 (x-x_k)}. \end{align}</math> Here, the [[sinc]]-function prevents any singularities and is defined by :<math> \mathrm{sinc}\,x=\frac{\sin x}{x}.</math>
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