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Fourier transform
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=== Fourier transform for periodic functions === The Fourier transform of a periodic function cannot be defined using the integral formula directly. In order for integral in {{EquationNote|Eq.1}} to be defined the function must be [[Absolutely integrable function|absolutely integrable]]. Instead it is common to use [[Fourier series]]. It is possible to extend the definition to include periodic functions by viewing them as [[Distribution (mathematics)#Tempered distributions|tempered distributions]]. This makes it possible to see a connection between the [[Fourier series]] and the Fourier transform for periodic functions that have a [[Convergence of Fourier series|convergent Fourier series]]. If <math>f(x)</math> is a [[periodic function]], with period <math>P</math>, that has a convergent Fourier series, then: <math display="block"> \widehat{f}(\xi) = \sum_{n=-\infty}^\infty c_n \cdot \delta \left(\xi - \tfrac{n}{P}\right), </math> where <math>c_n</math> are the Fourier series coefficients of <math>f</math>, and <math>\delta</math> is the [[Dirac delta function]]. In other words, the Fourier transform is a [[Dirac comb]] function whose ''teeth'' are multiplied by the Fourier series coefficients.
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