Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Tangent half-angle formula
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
==Rational values and Pythagorean triples== {{main article|Pythagorean triple}} Starting with a [[Pythagorean triangle]] with side lengths {{mvar|a}}, {{mvar|b}}, and {{mvar|c}} that are positive integers and satisfy {{math|''a''{{sup|2}} + ''b''{{sup|2}} {{=}} ''c''{{sup|2}}}}, it follows immediately that each [[interior angle]] of the triangle has rational values for sine and cosine, because these are just ratios of side lengths. Thus each of these angles has a rational value for its half-angle tangent, using {{math|tan ''Ο''/2 {{=}} sin ''Ο'' / (1 + cos ''Ο'')}}. The reverse is also true. If there are two positive angles that sum to 90Β°, each with a rational half-angle tangent, and the third angle is a [[right angle]] then a triangle with these interior angles can be [[similar (geometry)|scaled to]] a Pythagorean triangle. If the third angle is not required to be a right angle, but is the angle that makes the three positive angles sum to 180Β° then the third angle will necessarily have a rational number for its half-angle tangent when the first two do (using angle addition and subtraction formulas for tangents) and the triangle can be scaled to a [[Heronian triangle]]. Generally, if {{mvar|K}} is a [[Field extension|subfield]] of the complex numbers then {{math|tan ''Ο''/2 β ''K'' βͺ {{mset|β}}}} implies that {{math|{sin ''Ο'', cos ''Ο'', tan ''Ο'', sec ''Ο'', csc ''Ο'', cot ''Ο''} β ''K'' βͺ {{mset|β}}}}.
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)