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Wankel engine
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====Considering three chambers==== Eugen Wilhelm Huber, and Karl-Heinz Küttner counted all the chambers, since each one operates its own thermodynamic cycle. So <math>y = 3</math> and <math>n_c = 3</math>:<ref name="Wankel 1958 p. 16">{{cite patent |inventor-last=Wankel |inventor-first=Felix |title=Rotary internal combustion engine |issue-date=1958-11-17 |patent-number=2988065 |country-code=US}}, p. 16</ref><ref name="Huber 1960">{{cite journal|last1=Huber|first1=Eugen Wilhelm|title=Thermodynamische Untersuchungen an der Kreiskolbenmaschine|journal=VDI-Berichte|volume=45|year=1960|pages=13–29|language=de}}</ref><ref name="Küttner 1993 p. 391">{{cite book|last1=Küttner|first1=Karl-Heinz|title=Kolbenmaschinen|publisher=B. G. Teubner|date=1993|isbn=978-3-322-94040-7|doi=10.1007/978-3-322-94040-7|language=de|page=391}}</ref> :<math>P = p_{me} \cdot 3 \cdot V_k \cdot i \cdot {N \over 3}.</math> With these values, a single-rotor Wankel engine produces the same average power as a <math>V_h</math> three-cylinder four-stroke engine, with 3/2 of the average torque, with the shaft running at 2/3 the speed, operating the Otto cycles at the same frequency: :<math>P = p_{me} \cdot 3 \cdot V_k \cdot {{2 \over 3} N \over 2}.</math> Applying a 2/3 [[gear set]] to the output shaft of the three-cylinder (or a 3/2 one to the Wankel), the two are analogous from the thermodynamic and mechanical output point of view, as pointed out by Huber.<ref name="Huber 1960"/>
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