Editing Convex function (section)

== Uniformly convex functions ==
A uniformly convex function,<ref name="Zalinescu">{{cite book|title=Convex Analysis in General Vector Spaces|author=C. Zalinescu|publisher=World Scientific|year=2002|isbn=9812380671}}</ref><ref name="Bauschke">{{cite book|page=[https://archive.org/details/convexanalysismo00hhba/page/n161 144]|title=Convex Analysis and Monotone Operator Theory in Hilbert Spaces |url=https://archive.org/details/convexanalysismo00hhba|url-access=limited|author=H. Bauschke and P. L. Combettes |publisher=Springer |year=2011 |isbn=978-1-4419-9467-7}}</ref> with modulus <math>\phi</math>, is a function <math>f</math> that, for all <math>x, y</math> in the domain and <math>t \in [0, 1],</math> satisfies
<math display="block">f(tx+(1-t)y) \le t f(x)+(1-t)f(y) - t(1-t) \phi(\|x-y\|)</math>
where <math>\phi</math> is a function that is non-negative and vanishes only at&nbsp;0. This is a generalization of the concept of strongly convex function; by taking <math>\phi(\alpha) = \tfrac{m}{2} \alpha^2</math> we recover the definition of strong convexity.

It is worth noting that some authors require the modulus <math>\phi</math> to be an increasing function,<ref name="Bauschke">{{cite book|page=[https://archive.org/details/convexanalysismo00hhba/page/n161 144]|title=Convex Analysis and Monotone Operator Theory in Hilbert Spaces |url=https://archive.org/details/convexanalysismo00hhba|url-access=limited|author=H. Bauschke and P. L. Combettes |publisher=Springer |year=2011 |isbn=978-1-4419-9467-7}}</ref> but this condition is not required by all authors.<ref name="Zalinescu">{{cite book|title=Convex Analysis in General Vector Spaces|author=C. Zalinescu|publisher=World Scientific|year=2002|isbn=9812380671}}</ref>