Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
E (mathematical constant)
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
=== Optimal planning problems === The maximum value of <math>\sqrt[x]{x}</math> occurs at <math>x = e</math>. Equivalently, for any value of the base {{math|''b'' > 1}}, it is the case that the maximum value of <math>x^{-1}\log_b x</math> occurs at <math>x = e</math> ([[Steiner's calculus problem|Steiner's problem]], discussed [[#Exponential-like functions|below]]). This is useful in the problem of a stick of length {{mvar|L}} that is broken into {{mvar|n}} equal parts. The value of {{mvar|n}} that maximizes the product of the lengths is then either<ref name="Finch-2003-p14">{{cite book|title=Mathematical constants|url=https://archive.org/details/mathematicalcons0000finc|url-access=registration|author=Steven Finch|year=2003|publisher=Cambridge University Press|page=[https://archive.org/details/mathematicalcons0000finc/page/14 14]|isbn=978-0-521-81805-6}}</ref> :<math>n = \left\lfloor \frac{L}{e} \right\rfloor</math> or <math>\left\lceil \frac{L}{e} \right\rceil.</math> The quantity <math>x^{-1}\log_b x</math> is also a measure of [[Shannon information|information]] gleaned from an event occurring with probability <math>1/x</math> (approximately <math>36.8\%</math> when <math>x=e</math>), so that essentially the same optimal division appears in optimal planning problems like the [[secretary problem]].
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)