Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Isosceles triangle
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
==Isosceles subdivision of other shapes== [[File:Cyclic pentagon isosceles partition.svg|thumb|Partition of a [[cyclic polygon|cyclic pentagon]] into isosceles triangles by radii of its circumcircle]] For any integer <math>n \ge 4</math>, any [[triangle]] can be partitioned into <math>n</math> isosceles triangles.<ref>{{harvtxt|Lord|1982}}. See also {{harvtxt|Hadamard|2008|loc=Exercise 340, p. 270}}.</ref> In a [[right triangle]], the median from the hypotenuse (that is, the line segment from the midpoint of the hypotenuse to the right-angled vertex) divides the right triangle into two isosceles triangles. This is because the midpoint of the hypotenuse is the center of the [[circumcircle]] of the right triangle, and each of the two triangles created by the partition has two equal radii as two of its sides.{{sfnp|Posamentier|Lehmann|2012|page=24}} Similarly, an [[acute triangle]] can be partitioned into three isosceles triangles by segments from its circumcenter,{{sfnp|Bezdek|Bisztriczky|2015}} but this method does not work for obtuse triangles, because the circumcenter lies outside the triangle.{{sfnp|Harris|Stöcker|1998|page=75}} Generalizing the partition of an acute triangle, any [[cyclic polygon]] that contains the center of its circumscribed circle can be partitioned into isosceles triangles by the radii of this circle through its vertices. The fact that all radii of a circle have equal length implies that all of these triangles are isosceles. This partition can be used to derive a formula for the area of the polygon as a function of its side lengths, even for cyclic polygons that do not contain their circumcenters. This formula generalizes [[Heron's formula]] for triangles and [[Brahmagupta's formula]] for [[cyclic quadrilateral]]s.{{sfnp|Robbins|1995}} Either [[diagonal]] of a [[rhombus]] divides it into two [[Congruence (geometry)|congruent]] isosceles triangles. Similarly, one of the two diagonals of a [[Kite (geometry)|kite]] divides it into two isosceles triangles, which are not congruent except when the kite is a rhombus.{{sfnp|Usiskin|Griffin|2008|page=51}}
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)