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Lorentz transformation
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===Transformation of other quantities=== In general, given four quantities {{mvar|A}} and {{math|1='''Z''' = (''Z''{{sub|''x''}}, ''Z''{{sub|''y''}}, ''Z''{{sub|''z''}})}} and their Lorentz-boosted counterparts {{mvar|A′}} and {{math|1='''Z′''' = (''Z′''{{sub|''x''}}, ''Z′''{{sub|''y''}}, ''Z′''{{sub|''z''}})}}, a relation of the form <math display="block">A^2 - \mathbf{Z}\cdot\mathbf{Z} = {A'}^2 - \mathbf{Z}'\cdot\mathbf{Z}'</math> implies the quantities transform under Lorentz transformations similar to the transformation of spacetime coordinates; <math display="block">\begin{align} A' &= \gamma \left(A - \frac{v\mathbf{n}\cdot \mathbf{Z}}{c} \right) \,, \\ \mathbf{Z}' &= \mathbf{Z} + (\gamma-1)(\mathbf{Z}\cdot\mathbf{n})\mathbf{n} - \frac{\gamma A v\mathbf{n}}{c} \,. \end{align}</math> The decomposition of {{math|'''Z'''}} (and {{math|'''Z′'''}}) into components perpendicular and parallel to {{math|'''v'''}} is exactly the same as for the position vector, as is the process of obtaining the inverse transformations (exchange {{math|(''A'', '''Z''')}} and {{math|(''A′'', '''Z′''')}} to switch observed quantities, and reverse the direction of relative motion by the substitution {{math|'''n''' ↦ −'''n'''}}). The quantities {{math|(''A'', '''Z''')}} collectively make up a ''[[four-vector]]'', where {{mvar|A}} is the "timelike component", and {{math|'''Z'''}} the "spacelike component". Examples of {{mvar|A}} and {{math|'''Z'''}} are the following: {| class="wikitable" |- ! Four-vector ! {{mvar|A}} ! {{math|'''Z'''}} |- | Position [[four-vector]] | [[Time]] (multiplied by {{mvar|c}}), {{math|''ct''}} | [[Position vector]], {{math|'''r'''}} |- | [[Four-momentum]] | [[Energy]] (divided by {{mvar|c}}), {{math|''E''/''c''}} | [[Momentum]], {{math|'''p'''}} |- | [[Four-vector|Four-wave vector]] | [[angular frequency]] (divided by {{mvar|c}}), {{math|''ω''/''c''}} | [[wave vector]], {{math|'''k'''}} |- | [[Four-spin]] | (No name), {{math|''s''{{sub|''t''}}}} | [[Spin (physics)|Spin]], {{math|'''s'''}} |- | [[Four-current]] | [[Charge density]] (multiplied by {{mvar|c}}), {{math|''ρc''}} | [[Current density]], {{math|'''j'''}} |- | [[Electromagnetic four-potential]] | [[Electric potential]] (divided by {{mvar|c}}), {{math|''φ''/''c''}} | [[Magnetic vector potential]], {{math|'''A'''}} |} For a given object (e.g., particle, fluid, field, material), if {{mvar|A}} or {{math|'''Z'''}} correspond to properties specific to the object like its [[charge density]], [[mass density]], [[Spin (physics)|spin]], etc., its properties can be fixed in the rest frame of that object. Then the Lorentz transformations give the corresponding properties in a frame moving relative to the object with constant velocity. This breaks some notions taken for granted in non-relativistic physics. For example, the energy {{mvar|E}} of an object is a scalar in non-relativistic mechanics, but not in relativistic mechanics because energy changes under Lorentz transformations; its value is different for various inertial frames. In the rest frame of an object, it has a [[rest energy]] and zero momentum. In a boosted frame its energy is different and it appears to have a momentum. Similarly, in non-relativistic quantum mechanics the spin of a particle is a constant vector, but in [[relativistic quantum mechanics]] spin {{math|'''s'''}} depends on relative motion. In the rest frame of the particle, the spin pseudovector can be fixed to be its ordinary non-relativistic spin with a zero timelike quantity {{math|''s''{{sub|''t''}}}}, however a boosted observer will perceive a nonzero timelike component and an altered spin.<ref>{{harvnb|Chaichian|Hagedorn|1997|page=239}}</ref> Not all quantities are invariant in the form as shown above, for example orbital [[angular momentum]] {{math|'''L'''}} does not have a timelike quantity, and neither does the [[electric field]] {{math|'''E'''}} nor the [[magnetic field]] {{math|'''B'''}}. The definition of angular momentum is {{math|1='''L''' = '''r''' × '''p'''}}, and in a boosted frame the altered angular momentum is {{math|1='''L′''' = '''r′''' × '''p′'''}}. Applying this definition using the transformations of coordinates and momentum leads to the transformation of angular momentum. It turns out {{math|'''L'''}} transforms with another vector quantity {{math|1='''N''' = (''E''/''c''{{sup|2}})'''r''' − ''t'''''p'''}} related to boosts, see [[relativistic angular momentum]] for details. For the case of the {{math|'''E'''}} and {{math|'''B'''}} fields, the transformations cannot be obtained as directly using vector algebra. The [[Lorentz force]] is the definition of these fields, and in {{mvar|F}} it is {{math|1='''F''' = ''q''('''E''' + '''v''' × '''B''')}} while in {{mvar|F′}} it is {{math|1='''F′''' = ''q''('''E′''' + '''v′''' × '''B′''')}}. A method of deriving the EM field transformations in an efficient way which also illustrates the unit of the electromagnetic field uses tensor algebra, [[Lorentz transformation#Transformation of the electromagnetic field|given below]].
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