Editing Projectile motion (section)

=== Maximum height of projectile ===
[[File:Ferde hajitas4.svg|thumb|250px|Maximum height of projectile]]
The greatest height that the object will reach is known as the peak of the object's motion.
The increase in height will last until <math> v_y=0 </math>, that is,
:<math> 0=v_0 \sin(\theta) - gt_h </math>.
Time to reach the maximum height(h):
:<math display="inline"> t_h = \frac{v_0 \sin(\theta)}{|g|} </math>.
For the vertical displacement of the maximum height of the projectile:
:<math> h = v_0 t_h \sin(\theta) - \frac{1}{2} gt^2_h </math>
:<math> h = \frac{v_0^2 \sin^2(\theta)}{2|g|} </math>
The maximum reachable height is obtained for ''&theta;''=90°:
:<math> h_{\mathrm{max}} = \frac{v_0^2}{2|g|} </math>

If the projectile's position (x,y) and launch angle (θ) are known, the maximum height can be found by solving for h in the following equation:
:<math>h=\frac{(x\tan\theta)^2}{4(x\tan\theta-y)}. </math>

Angle of [[elevation]] (φ) at the maximum height is given by:
:<math>\phi = \arctan{{\tan\theta\over 2}}</math>
{{clear}}