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Threefold repetition
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===Kasparov vs. Deep Blue, 1997=== {{Chess diagram |tright |Kasparov vs. Deep Blue, 1997 | | | | | | | | |pd|pd| | | | |pl| | | | | | | | | | | | | | | | | | |kd|pd| | |nl| | | |nd| | |rl| |pl| | | | |rd| | | | | |kl| | | | | | |Position after 49...Kb4 }} In the [[Deep Blue versus Garry Kasparov#1997 game 5|game]]<ref>{{cite web|url=http://www.chessgames.com/perl/chessgame?gid=1070916 |title=Kasparov vs. Deep Blue, 1997 |publisher=Chessgames.com |access-date=2020-07-03}}</ref> between [[Garry Kasparov]] and [[Deep Blue (chess computer)|Deep Blue]] in New York 1997, the game ended with a [[draw by agreement]], because after 49...Kb4 ({{em|diagram}}), if White plays 50.g8=Q, Black can force perpetual check and claim a draw after 54.Kb1 by threefold repetition:<ref>{{Harvcol|Hsu|2002|pp=251β52}}</ref> :50...Rd1+ :51.Ka2, Kb2 or Kc2 Rd2+ :52.Kb1 (second time) Rd1+ :53.Ka2, Kb2 or Kc2 Rd2+ :54.Kb1 (third time) {{clear}}
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