Template:Short description The following is a list of integrals of exponential functions. For a complete list of integral functions, please see the list of integrals.
Indefinite integralEdit
Indefinite integrals are antiderivative functions. A constant (the constant of integration) may be added to the right hand side of any of these formulas, but has been suppressed here in the interest of brevity.
Integrals of polynomialsEdit
- <math>
\int xe^{cx}\,dx = e^{cx}\left(\frac{cx-1}{c^{2}}\right) \qquad \text{ for } c \neq 0; </math>
- <math>\int x^2 e^{cx}\,dx = e^{cx}\left(\frac{x^2}{c}-\frac{2x}{c^2}+\frac{2}{c^3}\right)</math>
- <math>\begin{align}
\int x^n e^{cx}\,dx &= \frac{1}{c} x^n e^{cx} - \frac{n}{c}\int x^{n-1} e^{cx} \,dx \\ &= \left( \frac{\partial}{\partial c} \right)^n \frac{e^{cx}}{c} \\ &= e^{cx}\sum_{i=0}^n (-1)^i\frac{n!}{(n-i)!c^{i+1}}x^{n-i} \\ &= e^{cx}\sum_{i=0}^n (-1)^{n-i}\frac{n!}{i!c^{n-i+1}}x^i \end{align}</math>
- <math>\int\frac{e^{cx}}{x}\,dx = \ln|x| +\sum_{n=1}^\infty\frac{(cx)^n}{n\cdot n!}</math>
- <math>\int\frac{e^{cx}}{x^n}\,dx = \frac{1}{n-1}\left(-\frac{e^{cx}}{x^{n-1}}+c\int\frac{e^{cx} }{x^{n-1}}\,dx\right) \qquad\text{(for }n\neq 1\text{)}</math>
Integrals involving only exponential functionsEdit
- <math>\int f'(x)e^{f(x)}\,dx = e^{f(x)}</math>
- <math>\int e^{cx}\,dx = \frac{1}{c} e^{cx}</math>
- <math>\int a^{x}\,dx = \frac{a^x}{\ln a}\qquad\text{ for }a > 0,\ a \ne 1</math>
Integrals involving the error functionEdit
In the following formulas, Template:Math is the error function and Template:Math is the exponential integral.
- <math>\int e^{cx}\ln x\,dx = \frac{1}{c}\left(e^{cx}\ln|x|-\operatorname{Ei}(cx)\right)</math>
- <math>\int x e^{c x^2 }\,dx= \frac{1}{2c} e^{c x^2}</math>
- <math>\int e^{-c x^2 }\,dx= \sqrt{\frac{\pi}{4c}} \operatorname{erf}(\sqrt{c} x)</math>
- <math>\int xe^{-c x^2 }\,dx=-\frac{1}{2c}e^{-cx^2} </math>
- <math>\int\frac{e^{-x^2}}{x^2}\,dx = -\frac{e^{-x^2}}{x} - \sqrt{\pi} \operatorname{erf} (x) </math>
- <math>\int {\frac{1}{\sigma\sqrt{2\pi}} e^{ -\frac{1}{2}\left(\frac{x-\mu}{\sigma}\right)^2 }}\,dx= \frac{1}{2}\operatorname{erf}\left(\frac{x-\mu}{\sigma \sqrt{2}}\right)</math>
Other integralsEdit
- <math>\int e^{x^2}\,dx = e^{x^2}\left( \sum_{j=0}^{n-1}c_{2j}\frac{1}{x^{2j+1}} \right )+(2n-1)c_{2n-2} \int \frac{e^{x^2}}{x^{2n}}\,dx \quad \text{valid for any } n > 0,
</math>
where <math> c_{2j}=\frac{ 1 \cdot 3 \cdot 5 \cdots (2j-1)}{2^{j+1}}=\frac{(2j)!}{j!2^{2j+1}} \ . </math>
(Note that the value of the expression is independent of the value of Template:Mvar, which is why it does not appear in the integral.)
- <math> {\int \underbrace{x^{x^{\cdot^{\cdot^{x}}}}}_mdx= \sum_{n=0}^m\frac{(-1)^n(n+1)^{n-1}}{n!}\Gamma(n+1,- \ln x) + \sum_{n=m+1}^\infty(-1)^na_{mn}\Gamma(n+1,-\ln x) \qquad\text{(for }x> 0\text{)}}</math>
where <math>a_{mn}=\begin{cases}1 &\text{if } n = 0, \\ \\ \dfrac{1}{n!} &\text{if } m=1, \\ \\ \dfrac{1}{n}\sum_{j=1}^{n}ja_{m,n-j}a_{m-1,j-1} &\text{otherwise} \end{cases}</math>
and Template:Math is the upper incomplete gamma function.
- <math>\int \frac{1}{ae^{\lambda x} + b} \,dx = \frac{x}{b} - \frac{1}{b \lambda} \ln\left(a e^{\lambda x} + b \right) </math> when <math>b \neq 0</math>, <math>\lambda \neq 0</math>, and <math>ae^{\lambda x} + b > 0.</math>
- <math>\int \frac{e^{2\lambda x}}{ae^{\lambda x} + b} \,dx = \frac{1}{a^2 \lambda} \left[a e^{\lambda x} + b - b \ln\left(a e^{\lambda x} + b \right) \right] </math> when <math>a \neq 0</math>, <math>\lambda \neq 0</math>, and <math>ae^{\lambda x} + b > 0.</math>
- <math>\int \frac{ae^{cx}-1}{be^{cx}-1}\,dx=\frac{(a-b)\log(1-be^{cx})}{bc}+x.</math>
- <math>\int{e^{x}\left( f\left( x \right) + f'\left( x \right) \right)\text{dx}} = e^{x}f\left( x \right) + C</math>
- <math>\int {e^{x}\left( f\left( x \right) - \left( - 1 \right)^{n}\frac{d^{n}f\left( x \right)}{dx^{n}} \right)\,dx} = e^{x}\sum_{k = 1}^{n}{\left( - 1 \right)^{k - 1}\frac{d^{k - 1}f\left( x \right)}{dx^{k - 1}}} + C</math>
- <math>\int {e^{- x}\left( f\left( x \right) - \frac{d^{n}f\left( x \right)}{dx^{n}} \right)\, dx} = - e^{- x}\sum_{k = 1}^{n}\frac{d^{k - 1}f\left( x \right)}{dx^{k - 1}} + C</math>
Template:EndplainlistTemplate:Startplainlist
- <math>\int {e^{ax}\left( \left( a\right)^{n}f\left( x \right) - \left( - 1 \right)^{n}\frac{d^{n}f\left( x \right)}{dx^{n}} \right)\,dx} = e^{ax}\sum_{k = 1}^{n}{\left(a\right)^{n-k}\left( - 1 \right)^{k - 1}\frac{d^{k - 1}f\left( x \right)}{dx^{k - 1}}} + C</math>
Definite integralsEdit
- <math>\begin{align}
\int_0^1 e^{x\cdot \ln a + (1-x)\cdot \ln b}\,dx &= \int_0^1 \left(\frac{a}{b}\right)^{x}\cdot b\,dx \\ &= \int_0^1 a^{x}\cdot b^{1-x}\,dx \\ &= \frac{a-b}{\ln a - \ln b} \qquad\text{for } a > 0,\ b > 0,\ a \neq b \end{align}</math>
The last expression is the logarithmic mean.
- <math>\int_0^{\infty} e^{-ax}\,dx=\frac{1}{a} \quad (\operatorname{Re}(a)>0)</math>
- <math>\int_0^{\infty} e^{-ax^2}\,dx=\frac{1}{2} \sqrt{\pi \over a} \quad (a>0)</math> (the Gaussian integral)
- <math>\int_{-\infty}^{\infty} e^{-ax^2}\,dx=\sqrt{\pi \over a} \quad (a>0)</math>
- <math>\int_{-\infty}^{\infty} e^{-ax^2} e^{-\frac{b}{x^2}}\,dx=\sqrt{\frac{\pi}{a}}e^{-2\sqrt{ab}} \quad (a,b>0) </math>
- <math>\int_{-\infty}^{\infty} e^{-(ax^2 + bx)}\,dx= \sqrt{\pi \over a}e^{\tfrac{b^2}{4a}} \quad(a > 0)</math>
- <math>\int_{-\infty}^{\infty} e^{-(ax^2 + bx+c)}\,dx= \sqrt{\pi \over a}e^{\tfrac{b^2}{4a}-c} \quad(a > 0)</math>
- <math>\int_{-\infty}^{\infty} e^{-ax^2} e^{-2bx}\,dx=\sqrt{\frac{\pi}{a}}e^{\frac{b^2}{a}} \quad (a>0)</math> (see Integral of a Gaussian function)
- <math>\int_{-\infty}^{\infty} x e^{-a(x-b)^2}\,dx= b \sqrt{\frac{\pi}{a}} \quad (\operatorname{Re}(a)>0)</math>
- <math>\int_{-\infty}^{\infty} x e^{-ax^2+bx}\,dx= \frac{ \sqrt{\pi} b }{2a^{3/2}} e^{\frac{b^2}{4a}} \quad (\operatorname{Re}(a)>0)</math>
- <math>\int_{-\infty}^{\infty} x^2 e^{-ax^2}\,dx=\frac{1}{2} \sqrt{\pi \over a^3} \quad (a>0)</math>
- <math>\int_{-\infty}^{\infty} x^2 e^{-(ax^2+bx)}\,dx=\frac{\sqrt{\pi}(2a+b^2)}{4a^{5/2}} e^{\frac{b^2}{4a}} \quad (\operatorname{Re}(a)>0)</math>
- <math>\int_{-\infty}^{\infty} x^3 e^{-(ax^2+bx)}\,dx=\frac{\sqrt{\pi}(6a+b^2)b}{8a^{7/2}} e^{\frac{b^2}{4a}} \quad (\operatorname{Re}(a)>0)</math>
- <math>\int_0^{\infty} x^{n} e^{-ax^2}\,dx =
\begin{cases} \dfrac{\Gamma \left(\frac{n+1}{2}\right)}{2 a^\frac{n+1}{2} } & (n>-1,\ a>0) \\ \dfrac{(2k-1)!!}{2^{k+1}a^k}\sqrt{\dfrac{\pi}{a}} & (n=2k,\ k \text{ integer},\ a>0) \\ \dfrac{k!}{2(a^{k+1})} & (n=2k+1,\ k \text{ integer},\ a>0) \end{cases}</math>
(the operator <math>!!</math> is the Double factorial)
- <math>\int_0^{\infty} x^n e^{-ax}\,dx =
\begin{cases} \dfrac{\Gamma(n+1)}{a^{n+1}} & (n>-1,\ \operatorname{Re}(a)>0) \\ \\ \dfrac{n!}{a^{n+1}} & (n=0,1,2,\ldots,\ \operatorname{Re}(a)>0) \end{cases}</math>
- <math>\int_0^{1} x^n e^{-ax}\,dx =
\frac{n!}{a^{n+1}}\left[1-e^{-a}\sum_{i=0}^{n} \frac{a^i}{i!}\right]</math>
- <math>\int_0^{b} x^n e^{-ax}\,dx =
\frac{n!}{a^{n+1}}\left[1-e^{-ab}\sum_{i=0}^{n} \frac{(ab)^i}{i!}\right]</math>
- <math>\int_0^\infty e^{-ax^b} dx = \frac{1}{b}\ a^{-\frac{1}{b}}\Gamma\left(\frac{1}{b}\right)</math>
- <math>\int_0^\infty x^n e^{-ax^b} dx = \frac{1}{b}\ a^{-\frac{n+1}{b}}\Gamma\left(\frac{n+1}{b}\right)</math>
- <math>\int_0^{\infty} e^{-ax}\sin bx\,dx = \frac{b}{a^2+b^2} \quad (a>0)</math>
- <math>\int_0^{\infty} e^{-ax}\cos bx\,dx = \frac{a}{a^2+b^2} \quad (a>0)</math>
- <math>\int_0^{\infty} xe^{-ax}\sin bx\,dx = \frac{2ab}{(a^2+b^2)^2} \quad (a>0)</math>
- <math>\int_0^{\infty} xe^{-ax}\cos bx\,dx = \frac{a^2-b^2}{(a^2+b^2)^2} \quad (a>0)</math>
- <math>\int_0^{\infty} \frac{e^{-ax}\sin bx}{x}\,dx=\arctan \frac{b}{a}</math>
- <math>\int_0^{\infty} \frac{e^{-ax}-e^{-bx}}{x}\,dx=\ln \frac{b}{a}</math>
- <math>\int_0^{\infty} \frac{e^{-ax}-e^{-bx}}{x} \sin px \, dx=\arctan \frac{b}{p} - \arctan \frac{a}{p}</math>
- <math>\int_0^{\infty} \frac{e^{-ax}-e^{-bx}}{x} \cos px \, dx=\frac{1}{2} \ln \frac{b^2+p^2}{a^2+p^2}</math>
- <math>\int_0^{\infty} \frac{e^{-ax} (1-\cos x)}{x^2}\,dx=\arccot a - \frac{a}{2}\ln \Big(\frac{1}{a^2}+1\Big)</math>
- <math> \int_{-\infty}^\infty e^{a x^4+b x^3+c x^2+d x+f} \, dx
= e^f \sum_{n,m,p=0}^\infty \frac{ b^{4n}}{(4n)!} \frac{c^{2m}}{(2m)!} \frac{d^{4p}}{(4p)!} \frac{ \Gamma(3n+m+p+\frac14) }{a^{3n+m+p+\frac14} } </math> (appears in several models of extended superstring theory in higher dimensions)
- <math>\int_0^{2 \pi} e^{x \cos \theta} d \theta = 2 \pi I_0(x)</math> (Template:Math is the modified Bessel function of the first kind)
- <math>\int_0^{2 \pi} e^{x \cos \theta + y \sin \theta} d \theta = 2 \pi I_0 \left( \sqrt{x^2 + y^2} \right)</math>
- <math>\int_0^\infty\frac{x^{s-1}}{e^x/z-1} \,dx = \operatorname{Li}_{s}(z)\Gamma(s), </math>
where <math>\operatorname{Li}_{s}(z)</math> is the Polylogarithm.
- <math>\int_0^\infty\frac{\sin mx}{e^{2 \pi x}-1} \,dx = \frac{1}{4} \coth \frac{m}{2} - \frac{1}{2m} </math>
- <math>\int_0^\infty e^{-x} \ln x\, dx = - \gamma, </math>
where <math>\gamma</math> is the Euler–Mascheroni constant which equals the value of a number of definite integrals.
Finally, a well known result, <math display="block">\int_0^{2 \pi} e^{i(m-n)\phi} d\phi = 2 \pi \delta_{m,n} \qquad\text{for }m,n\in\mathbb{Z}</math> where <math>\delta_{m,n}</math> is the Kronecker delta.
See alsoEdit
ReferencesEdit
Template:Reflist Toyesh Prakash Sharma, Etisha Sharma, "Putting Forward Another Generalization Of The Class Of Exponential Integrals And Their Applications.," International Journal of Scientific Research in Mathematical and Statistical Sciences, Vol.10, Issue.2, pp.1-8, 2023.[1]
Further readingEdit
- Template:Cite book
- Template:Cite book
- Toyesh Prakash Sharma, https://www.isroset.org/pdf_paper_view.php?paper_id=2214&7-ISROSET-IJSRMSS-05130.pdf
External linksEdit
- Wolfram Mathematica Online Integrator
- {{#invoke:citation/CS1|citation
|CitationClass=web }}