Field trace

{{#invoke:other uses|otheruses}} In mathematics, the field trace is a particular function defined with respect to a finite field extension L/K, which is a K-linear map from L onto K.

Definition

Let K be a field and L a finite extension (and hence an algebraic extension) of K. L can be viewed as a vector space over K. Multiplication by α, an element of L,

<math>m_\alpha:L\to L \text{ given by } m_\alpha (x) = \alpha x</math>,

is a K-linear transformation of this vector space into itself. The trace, Tr_L/K(α), is defined as the trace (in the linear algebra sense) of this linear transformation.<ref name=ROT940>Template:Harvnb</ref>

For α in L, let σ₁(α), ..., σ_n(α) be the roots (counted with multiplicity) of the minimal polynomial of α over K (in some extension field of K). Then

<math>\operatorname{Tr}_{L/K}(\alpha) = [L:K(\alpha)]\sum_{j=1}^n\sigma_j(\alpha).</math>

If L/K is separable then each root appears only once<ref>Template:Harvnb</ref> (however this does not mean the coefficient above is one; for example if α is the identity element 1 of K then the trace is [L:K] times 1).

More particularly, if L/K is a Galois extension and α is in L, then the trace of α is the sum of all the Galois conjugates of α,<ref name="ROT940" /> i.e.,

<math>\operatorname{Tr}_{L/K}(\alpha)=\sum_{\sigma\in\operatorname{Gal}(L/K)}\sigma(\alpha),</math>

where Gal(L/K) denotes the Galois group of L/K.

Example

Let <math>L = \mathbb{Q}(\sqrt{d})</math> be a quadratic extension of <math>\mathbb{Q}</math>. Then a basis of <math>L/\mathbb{Q}</math> is <math>\{1, \sqrt{d}\}.</math> If <math>\alpha = a + b\sqrt{d}</math> then the matrix of <math>m_{\alpha}</math> is:

<math>\left [ \begin{matrix} a & bd \\ b & a \end{matrix} \right ]</math>,

and so, <math>\operatorname{Tr}_{L/\mathbb{Q}}(\alpha) = [L:\mathbb{Q}(\alpha)]\left( \sigma_1(\alpha) + \sigma_2(\alpha)\right)

= 1\times \left( \sigma_1(\alpha) + \overline{\sigma_1}(\alpha)\right)
= a+b\sqrt{d} + a-b\sqrt{d} = 2a</math>.<ref name=ROT940/> The minimal polynomial of α is Template:Nowrap.

Properties of the trace

Several properties of the trace function hold for any finite extension.<ref>Template:Harvnb</ref>

The trace Template:Nowrap is a K-linear map (a K-linear functional), that is

<math>\operatorname{Tr}_{L/K}(\alpha a + \beta b) = \alpha \operatorname{Tr}_{L/K}(a)+ \beta \operatorname{Tr}_{L/K}(b) \text{ for all }\alpha, \beta \in K</math>.

If Template:Nowrap then <math>\operatorname{Tr}_{L/K}(\alpha) = [L:K] \alpha.</math>

Additionally, trace behaves well in towers of fields: if M is a finite extension of L, then the trace from M to K is just the composition of the trace from M to L with the trace from L to K, i.e.

<math>\operatorname{Tr}_{M/K}=\operatorname{Tr}_{L/K}\circ\operatorname{Tr}_{M/L}</math>.

Finite fields

Let L = GF(qⁿ) be a finite extension of a finite field K = GF(q). Since L/K is a Galois extension, if α is in L, then the trace of α is the sum of all the Galois conjugates of α, i.e.<ref name=LN54>Template:Harvnb</ref>

<math>\operatorname{Tr}_{L/K}(\alpha)=\alpha + \alpha^q + \cdots + \alpha^{q^{n-1}}.</math>

In this setting we have the additional properties:<ref>Template:Harvnb</ref>

• <math>\operatorname{Tr}_{L/K}(a^q) = \operatorname{Tr}_{L/K}(a) \text{ for } a \in L</math>.
• For any <math>\alpha \in K</math>, there are exactly <math> q^{n-1}</math> elements <math>b\in L</math> with <math>\operatorname{Tr}_{L/K}(b) = \alpha</math>.

Theorem.<ref name=LN56>Template:Harvnb</ref> For b ∈ L, let F_b be the map <math>a \mapsto \operatorname{Tr}_{L/K}(ba).</math> Then Template:Nowrap if Template:Nowrap. Moreover, the K-linear transformations from L to K are exactly the maps of the form F_b as b varies over the field L.

When K is the prime subfield of L, the trace is called the absolute trace and otherwise it is a relative trace.<ref name=LN54/>

Application

A quadratic equation, Template:Nowrap with a ≠ 0, and coefficients in the finite field <math>\operatorname{GF}(q) = \mathbb{F}_q</math> has either 0, 1 or 2 roots in GF(q) (and two roots, counted with multiplicity, in the quadratic extension GF(q²)). If the characteristic of GF(q) is odd, the discriminant Template:Nowrap indicates the number of roots in GF(q) and the classical quadratic formula gives the roots. However, when GF(q) has even characteristic (i.e., Template:Nowrap for some positive integer h), these formulas are no longer applicable.

Consider the quadratic equation Template:Nowrap with coefficients in the finite field GF(2^h).<ref>Template:Harvnb</ref> If b = 0 then this equation has the unique solution <math>x = \sqrt{\frac{c}{a}}</math> in GF(q). If Template:Nowrap then the substitution Template:Nowrap converts the quadratic equation to the form:

<math>y^2 + y + \delta = 0, \text { where } \delta = \frac{ac}{b^2}.</math>

This equation has two solutions in GF(q) if and only if the absolute trace <math>\operatorname{Tr}_{GF(q)/GF(2)}(\delta) = 0.</math> In this case, if y = s is one of the solutions, then y = s + 1 is the other. Let k be any element of GF(q) with <math>\operatorname{Tr}_{GF(q)/GF(2)}(k) = 1.</math> Then a solution to the equation is given by:

<math> y = s = k \delta^2 + (k + k^2)\delta^4 + \ldots + (k + k^2 + \ldots + k^{2^{h-2}})\delta^{2^{h-1}}.</math>

When h = 2m' + 1, a solution is given by the simpler expression:

<math> y = s = \delta + \delta^{2^2} + \delta^{2^4} + \ldots + \delta^{2^{2m}}.</math>

Trace form

When L/K is separable, the trace provides a duality theory via the trace form: the map from Template:Nowrap to K sending Template:Nowrap to Tr_L/K(xy) is a nondegenerate, symmetric bilinear form called the trace form. If L/K is a Galois extension, the trace form is invariant with respect to the Galois group.

The trace form is used in algebraic number theory in the theory of the different ideal.

The trace form for a finite degree field extension L/K has non-negative signature for any field ordering of K.<ref name=L38/> The converse, that every Witt equivalence class with non-negative signature contains a trace form, is true for algebraic number fields K.<ref name=L38>Lorenz (2008) p.38</ref>

If L/K is an inseparable extension, then the trace form is identically 0.<ref>Template:Harvnb as footnoted in Template:Harvnb</ref>

See also

• Field norm
• Reduced trace

References

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Further reading

• Template:Cite book
• Section VI.5 of Template:Lang Algebra