Periodic points of complex quadratic mappings
This article describes periodic points of some complex quadratic maps. A map is a formula for computing a value of a variable based on its own previous value or values; a quadratic map is one that involves the previous value raised to the powers one and two; and a complex map is one in which the variable and the parameters are complex numbers. A periodic point of a map is a value of the variable that occurs repeatedly after intervals of a fixed length.
These periodic points play a role in the theories of Fatou and Julia sets.
DefinitionsEdit
Let
- <math>f_c(z) = z^2+c\,</math>
be the complex quadratic mapping, where <math>z</math> and <math>c</math> are complex numbers.
Notationally, <math>f^{(k)} _c (z)</math> is the <math>k</math>-fold composition of <math>f_c</math> with itself (not to be confused with the <math>k</math>th derivative of <math>f_c</math>)—that is, the value after the k-th iteration of the function <math>f _c.</math> Thus
- <math>f^{(k)} _c (z) = f_c(f^{(k-1)} _c (z)).</math>
Periodic points of a complex quadratic mapping of period <math>p</math> are points <math>z</math> of the dynamical plane such that
- <math>f^{(p)} _c (z) = z,</math>
where <math>p</math> is the smallest positive integer for which the equation holds at that z.
We can introduce a new function:
- <math>F_p(z,f) = f^{(p)} _c (z) - z,</math>
so periodic points are zeros of function <math>F_p(z,f)</math>: points z satisfying
- <math>F_p(z,f) = 0,</math>
which is a polynomial of degree <math>2^p.</math>
Number of periodic pointsEdit
The degree of the polynomial <math>F_p(z,f)</math> describing periodic points is <math>d = 2^p</math> so it has exactly <math>d = 2^p</math> complex roots (= periodic points), counted with multiplicity.
Stability of periodic points (orbit) - multiplierEdit
The multiplier (or eigenvalue, derivative) <math>m(f^p,z_0)=\lambda</math> of a rational map <math>f</math> iterated <math>p</math> times at cyclic point <math>z_0</math> is defined as:
- <math>m(f^p,z_0) = \lambda = \begin{cases}
f^{p \prime}(z_0), &\mbox{if }z_0 \ne \infty \\ \frac{1}{f^{p \prime} (z_0)}, & \mbox{if }z_0 = \infty \end{cases}</math>
where <math>f^{p\prime} (z_0)</math> is the first derivative of <math>f^p</math> with respect to <math>z</math> at <math>z_0</math>.
Because the multiplier is the same at all periodic points on a given orbit, it is called a multiplier of the periodic orbit.
The multiplier is:
- a complex number;
- invariant under conjugation of any rational map at its fixed point;<ref>Alan F. Beardon, Iteration of Rational Functions, Springer 1991, Template:ISBN, p. 41</ref>
- used to check stability of periodic (also fixed) points with stability index <math>abs(\lambda). \,</math>
A periodic point is<ref>Alan F. Beardon, Iteration of Rational Functions, Springer 1991, Template:ISBN, page 99</ref>
- attracting when <math>abs(\lambda) < 1;</math>
- super-attracting when <math>abs(\lambda) = 0;</math>
- attracting but not super-attracting when <math>0 < abs(\lambda) < 1;</math>
- indifferent when <math>abs(\lambda) = 1;</math>
- rationally indifferent or parabolic if <math>\lambda</math> is a root of unity;
- irrationally indifferent if <math>abs(\lambda)=1</math> but multiplier is not a root of unity;
- repelling when <math>abs(\lambda) > 1.</math>
Periodic points
- that are attracting are always in the Fatou set;
- that are repelling are in the Julia set;
- that are indifferent fixed points may be in one or the other.<ref>Some Julia sets by Michael Becker</ref> A parabolic periodic point is in the Julia set.
Period-1 points (fixed points)Edit
Finite fixed pointsEdit
Let us begin by finding all finite points left unchanged by one application of <math>f</math>. These are the points that satisfy <math>f_c(z)=z</math>. That is, we wish to solve
- <math>z^2+c=z,\,</math>
which can be rewritten as
- <math>\ z^2-z+c=0.</math>
Since this is an ordinary quadratic equation in one unknown, we can apply the standard quadratic solution formula:
- <math>\alpha_1 = \frac{1-\sqrt{1-4c}}{2}</math> and <math>\alpha_2 = \frac{1+\sqrt{1-4c}}{2}.</math>
So for <math>c \in \mathbb{C} \setminus \{1/4\}</math> we have two finite fixed points <math>\alpha_1</math> and <math>\alpha_2</math>.
Since
- <math>\alpha_1 = \frac{1}{2}-m</math> and <math>\alpha_2 = \frac{1}{2}+m</math> where <math>m = \frac{\sqrt{1-4c}}{2},</math>
we have <math>\alpha_1 + \alpha_2 = 1</math>.
Thus fixed points are symmetrical about <math>z = 1/2</math>.
Complex dynamicsEdit
Here different notation is commonly used:<ref>On the regular leaf space of the cauliflower by Tomoki Kawahira Source: Kodai Math. J. Volume 26, Number 2 (2003), 167-178. Template:Webarchive</ref>
- <math>\alpha_c = \frac{1-\sqrt{1-4c}}{2}</math> with multiplier <math>\lambda_{\alpha_c} = 1-\sqrt{1-4c}</math>
and
- <math>\beta_c = \frac{1+\sqrt{1-4c}}{2}</math> with multiplier <math>\lambda_{\beta_c} = 1+\sqrt{1-4c}.</math>
Again we have
- <math>\alpha_c + \beta_c = 1 .</math>
Since the derivative with respect to z is
- <math>P_c'(z) = \frac{d}{dz}P_c(z) = 2z ,</math>
we have
- <math>P_c'(\alpha_c) + P_c'(\beta_c)= 2 \alpha_c + 2 \beta_c = 2 (\alpha_c + \beta_c) = 2 .</math>
This implies that <math>P_c</math> can have at most one attractive fixed point.
These points are distinguished by the facts that:
- <math>\beta_c</math> is:
- the landing point of the external ray for angle=0 for <math>c \in M \setminus \left\{ 1/4 \right\}</math>
- the most repelling fixed point of the Julia set
- the one on the right (whenever fixed point are not symmetrical around the real axis), it is the extreme right point for connected Julia sets (except for cauliflower).<ref>Periodic attractor by Evgeny Demidov Template:Webarchive</ref>
- <math>\alpha_c</math> is:
- the landing point of several rays
- attracting when <math>c</math> is in the main cardioid of the Mandelbrot set, in which case it is in the interior of a filled-in Julia set, and therefore belongs to the Fatou set (strictly to the basin of attraction of finite fixed point)
- parabolic at the root point of the limb of the Mandelbrot set
- repelling for other values of <math>c</math>
Special casesEdit
An important case of the quadratic mapping is <math>c=0</math>. In this case, we get <math>\alpha_1 = 0</math> and <math>\alpha_2=1</math>. In this case, 0 is a superattractive fixed point, and 1 belongs to the Julia set.
Only one fixed pointEdit
We have <math>\alpha_1=\alpha_2</math> exactly when <math>1-4c=0.</math> This equation has one solution, <math>c=1/4,</math> in which case <math>\alpha_1=\alpha_2=1/2</math>. In fact <math>c=1/4</math> is the largest positive, purely real value for which a finite attractor exists.
Infinite fixed pointEdit
We can extend the complex plane <math>\mathbb{C}</math> to the Riemann sphere (extended complex plane) <math>\mathbb{\hat{C}}</math> by adding infinity:
- <math>\mathbb{\hat{C}} = \mathbb{C} \cup \{ \infty \}</math>
and extend <math>f_c</math> such that <math>f_c(\infty)=\infty.</math>
Then infinity is:
- superattracting
- a fixed point of <math>f_c</math>:<ref>R L Devaney, L Keen (Editor): Chaos and Fractals: The Mathematics Behind the Computer Graphics. Publisher: Amer Mathematical Society July 1989, Template:ISBN , Template:ISBN</ref><math display="block">f_c(\infty)=\infty=f^{-1}_c(\infty).</math>
Period-2 cyclesEdit
Period-2 cycles are two distinct points <math>\beta_1</math> and <math>\beta_2</math> such that <math>f_c(\beta_1) = \beta_2</math> and <math>f_c(\beta_2) = \beta_1</math>, and hence
- <math>f_c(f_c(\beta_n)) = \beta_n</math>
for <math>n \in \{1, 2\}</math>:
- <math>f_c(f_c(z)) = (z^2+c)^2+c = z^4 + 2cz^2 + c^2 + c.</math>
Equating this to z, we obtain
- <math>z^4 + 2cz^2 - z + c^2 + c = 0.</math>
This equation is a polynomial of degree 4, and so has four (possibly non-distinct) solutions. However, we already know two of the solutions. They are <math>\alpha_1</math> and <math>\alpha_2</math>, computed above, since if these points are left unchanged by one application of <math>f</math>, then clearly they will be unchanged by more than one application of <math>f</math>.
Our 4th-order polynomial can therefore be factored in 2 ways:
First method of factorizationEdit
- <math>(z-\alpha_1)(z-\alpha_2)(z-\beta_1)(z-\beta_2) = 0.\,</math>
This expands directly as <math>x^4 - Ax^3 + Bx^2 - Cx + D = 0</math> (note the alternating signs), where
- <math>D = \alpha_1 \alpha_2 \beta_1 \beta_2, \,</math>
- <math>C = \alpha_1 \alpha_2 \beta_1 + \alpha_1 \alpha_2 \beta_2 + \alpha_1 \beta_1 \beta_2 + \alpha_2 \beta_1 \beta_2, \,</math>
- <math>B = \alpha_1 \alpha_2 + \alpha_1 \beta_1 + \alpha_1 \beta_2 + \alpha_2 \beta_1 + \alpha_2 \beta_2 + \beta_1 \beta_2, \,</math>
- <math>A = \alpha_1 + \alpha_2 + \beta_1 + \beta_2.\,</math>
We already have two solutions, and only need the other two. Hence the problem is equivalent to solving a quadratic polynomial. In particular, note that
- <math>\alpha_1 + \alpha_2 = \frac{1-\sqrt{1-4c}}{2} + \frac{1+\sqrt{1-4c}}{2} = \frac{1+1}{2} = 1</math>
and
- <math>\alpha_1 \alpha_2 = \frac{(1-\sqrt{1-4c})(1+\sqrt{1-4c})}{4} = \frac{1^2 - (\sqrt{1-4c})^2}{4}= \frac{1 - 1 + 4c}{4} = \frac{4c}{4} = c.</math>
Adding these to the above, we get <math>D = c \beta_1 \beta_2</math> and <math>A = 1 + \beta_1 + \beta_2</math>. Matching these against the coefficients from expanding <math>f</math>, we get
- <math>D = c \beta_1 \beta_2 = c^2 + c</math> and <math>A = 1 + \beta_1 + \beta_2 = 0.</math>
From this, we easily get
- <math>\beta_1 \beta_2 = c + 1</math> and <math>\beta_1 + \beta_2 = -1</math>.
From here, we construct a quadratic equation with <math>A' = 1, B = 1, C = c+1</math> and apply the standard solution formula to get
- <math>\beta_1 = \frac{-1 - \sqrt{-3 -4c}}{2}</math> and <math>\beta_2 = \frac{-1 + \sqrt{-3 -4c}}{2}.</math>
Closer examination shows that:
- <math>f_c(\beta_1) = \beta_2</math> and <math>f_c(\beta_2) = \beta_1,</math>
meaning these two points are the two points on a single period-2 cycle.
Second method of factorizationEdit
We can factor the quartic by using polynomial long division to divide out the factors <math>(z-\alpha_1)</math> and <math>(z-\alpha_2), </math> which account for the two fixed points <math>\alpha_1</math> and <math>\alpha_2</math> (whose values were given earlier and which still remain at the fixed point after two iterations):
- <math>(z^2+c)^2 + c -z = (z^2 + c - z)(z^2 + z + c +1 ). \,</math>
The roots of the first factor are the two fixed points. They are repelling outside the main cardioid.
The second factor has the two roots
- <math>\frac{-1 \pm \sqrt{-3 -4c}}{2}. \,</math>
These two roots, which are the same as those found by the first method, form the period-2 orbit.<ref>Period 2 orbit by Evgeny Demidov Template:Webarchive</ref>
Special casesEdit
Again, let us look at <math>c=0</math>. Then
- <math>\beta_1 = \frac{-1 - i\sqrt{3}}{2}</math> and <math>\beta_2 = \frac{-1 + i\sqrt{3}}{2},</math>
both of which are complex numbers. We have <math>| \beta_1 | = | \beta_2 | = 1</math>. Thus, both these points are "hiding" in the Julia set. Another special case is <math>c=-1</math>, which gives <math>\beta_1 = 0</math> and <math>\beta_2 = -1</math>. This gives the well-known superattractive cycle found in the largest period-2 lobe of the quadratic Mandelbrot set.
Cycles for period greater than 2Edit
The degree of the equation <math>f^{(n)}(z)=z</math> is 2n; thus for example, to find the points on a 3-cycle we would need to solve an equation of degree 8. After factoring out the factors giving the two fixed points, we would have a sixth degree equation.
There is no general solution in radicals to polynomial equations of degree five or higher, so the points on a cycle of period greater than 2 must in general be computed using numerical methods. However, in the specific case of period 4 the cyclical points have lengthy expressions in radicals.<ref>Gvozden Rukavina : Quadratic recurrence equations - exact explicit solution of period four fixed points functions in bifurcation diagram</ref>
In the case c = –2, trigonometric solutions exist for the periodic points of all periods. The case <math>z_{n+1}=z_n^2-2</math> is equivalent to the logistic map case r = 4: <math>x_{n+1}=4x_n(1-x_n).</math> Here the equivalence is given by <math>z=2-4x.</math> One of the k-cycles of the logistic variable x (all of which cycles are repelling) is
- <math>\sin^2\left(\frac{2\pi}{2^k-1}\right), \, \sin^2\left(2\cdot\frac{2\pi}{2^k-1}\right), \, \sin^2\left(2^2\cdot\frac{2\pi}{2^k-1}\right), \, \sin^2\left(2^3\cdot\frac{2\pi}{2^k-1}\right), \dots , \sin^2\left(2^{k-1}\frac{2\pi}{2^k-1}\right).</math>
ReferencesEdit
Further readingEdit
- Geometrical properties of polynomial roots
- Alan F. Beardon, Iteration of Rational Functions, Springer 1991, Template:ISBN
- Michael F. Barnsley (Author), Stephen G. Demko (Editor), Chaotic Dynamics and Fractals (Notes and Reports in Mathematics in Science and Engineering Series) Academic Pr (April 1986), Template:ISBN
- Wolf Jung : Homeomorphisms on Edges of the Mandelbrot Set. Ph.D. thesis of 2002
- The permutations of periodic points in quadratic polynominials by J Leahy
External linksEdit
- Algebraic solution of Mandelbrot orbital boundaries by Donald D. Cross
- Brown Method by Robert P. Munafo
- arXiv:hep-th/0501235v2 V.Dolotin, A.Morozov: Algebraic Geometry of Discrete Dynamics. The case of one variable.