Pell's equation
Template:Short description Template:Good article Template:Use dmy dates
Pell's equation, also called the Pell–Fermat equation, is any Diophantine equation of the form <math>x^2 - ny^2 = 1,</math> where n is a given positive nonsquare integer, and integer solutions are sought for x and y. In Cartesian coordinates, the equation is represented by a hyperbola; solutions occur wherever the curve passes through a point whose x and y coordinates are both integers, such as the trivial solution with x = 1 and y = 0. Joseph Louis Lagrange proved that, as long as n is not a perfect square, Pell's equation has infinitely many distinct integer solutions. These solutions may be used to accurately approximate the square root of n by rational numbers of the form x/y.
This equation was first studied extensively in India starting with Brahmagupta,<ref>{{#invoke:citation/CS1|citation |CitationClass=web }}</ref> who found an integer solution to <math>92x^2 + 1 = y^2</math> in his Brāhmasphuṭasiddhānta circa 628.<ref>{{#invoke:citation/CS1|citation |CitationClass=web }}</ref> Bhaskara II in the 12th century and Narayana Pandit in the 14th century both found general solutions to Pell's equation and other quadratic indeterminate equations. Bhaskara II is generally credited with developing the chakravala method, building on the work of Jayadeva and Brahmagupta. Solutions to specific examples of Pell's equation, such as the Pell numbers arising from the equation with n = 2, had been known for much longer, since the time of Pythagoras in Greece and a similar date in India. William Brouncker was the first European to solve Pell's equation. The name of Pell's equation arose from Leonhard Euler mistakenly attributing Brouncker's solution of the equation to John Pell.<ref>As early as 1732–1733 Euler believed that John Pell had developed a method to solve Pell's equation, even though Euler knew that Wallis had developed a method to solve it (although William Brouncker had actually done most of the work):
- Template:Cite journal From p. 182: "At si a huiusmodi fuerit numerus, qui nullo modo ad illas formulas potest reduci, peculiaris ad invenienda p et q adhibenda est methodus, qua olim iam usi sunt Pellius et Fermatius." (But if such an a be a number that can be reduced in no way to these formulas, the specific method for finding p and q is applied which Pell and Fermat have used for some time now.) From p. 183: "§. 19. Methodus haec extat descripta in operibus Wallisii, et hanc ob rem eam hic fusius non-expono." (§ 19. This method exists described in the works of Wallis, and for this reason I do not present it here in more detail.)
- Lettre IX. Euler à Goldbach, dated 10 August 1750 in: Template:Cite book From page 37: {{#invoke:Lang|lang}} (For solving such questions, the Englishman Dr. Pell devised a singular method [which is] shown in Wallis' works.)
- Template:Cite book From p. 227: {{#invoke:Lang|lang}} (§ 98 Concerning this, a learned Englishman by the name of Pell has previously found a quite ingenious method, which we will explain here.)
- English translation: Template:Cite book
- Template:Cite book See especially footnote 4.</ref><ref name=":1" /><ref group=note>In Euler's {{#invoke:Lang|lang}} (pp. 227ff), he presents a solution to Pell's equation which was taken from John Wallis' {{#invoke:Lang|lang}}, specifically, Letter 17 ({{#invoke:Lang|lang}}) and Letter 19 ({{#invoke:Lang|lang}}) of:
- Template:Cite book The letters are in Latin. Letter 17 appears on pp. 56–72. Letter 19 appears on pp. 81–91.
- French translations of Wallis' letters: Template:Cite book Letter 17 appears on pp. 457–480. Letter 19 appears on pp. 490–503.
Wallis' letters showing a solution to the Pell's equation also appear in volume 2 of Wallis' {{#invoke:Lang|lang}} (1693), which includes articles by John Pell:
- Template:Cite book Letter 17 is on pp. 789–798; letter 19 is on pp. 802–806. See also Pell's articles, where Wallis mentions (pp. 235, 236, 244) that Pell's methods are applicable to the solution of Diophantine equations:
- {{#invoke:Lang|lang}} (On Algebra by Dr. John Pell and especially on an incompletely determined problem), pp. 234–236.
- {{#invoke:Lang|lang}} (Example of Pell's method), pp. 238–244.
- {{#invoke:Lang|lang}} (Another example of Pell's method), pp. 244–246.
See also:
- Whitford, Edward Everett (1912) "The Pell equation", doctoral thesis, Columbia University (New York, New York, USA), p. 52.
- Template:Cite book</ref>
HistoryEdit
As early as 400 BC in India and Greece, mathematicians studied the numbers arising from the n = 2 case of Pell's equation, <math display="block">x^2 - 2 y^2 = 1,</math> and from the closely related equation <math display="block">x^2 - 2 y^2 = -1</math> because of the connection of these equations to the square root of 2.<ref name="knorr76"/> Indeed, if x and y are positive integers satisfying this equation, then x/y is an approximation of Template:Math. The numbers x and y appearing in these approximations, called side and diameter numbers, were known to the Pythagoreans, and Proclus observed that in the opposite direction these numbers obeyed one of these two equations.<ref name="knorr76"/> Similarly, Baudhayana discovered that x = 17, y = 12 and x = 577, y = 408 are two solutions to the Pell equation, and that 17/12 and 577/408 are very close approximations to the square root of 2.<ref>Template:MacTutor Biography</ref>
Later, Archimedes approximated the square root of 3 by the rational number 1351/780. Although he did not explain his methods, this approximation may be obtained in the same way, as a solution to Pell's equation.<ref name="knorr76">Template:Citation.</ref> Likewise, Archimedes's cattle problem — an ancient word problem about finding the number of cattle belonging to the sun god Helios — can be solved by reformulating it as a Pell's equation. The manuscript containing the problem states that it was devised by Archimedes and recorded in a letter to Eratosthenes,<ref>Template:Cite journal</ref> and the attribution to Archimedes is generally accepted today.<ref>Template:Cite book</ref><ref>Template:Cite book</ref>
Around AD 250, Diophantus considered the equation <math display="block">a^2 x^2 + c = y^2,</math> where a and c are fixed numbers, and x and y are the variables to be solved for. This equation is different in form from Pell's equation but equivalent to it. Diophantus solved the equation for (a, c) equal to (1, 1), (1, −1), (1, 12), and (3, 9). Al-Karaji, a 10th-century Persian mathematician, worked on similar problems to Diophantus.<ref>Template:Cite journal</ref>
In Indian mathematics, Brahmagupta discovered that <math display="block">(x_1^2 - Ny_1^2)(x_2^2 - Ny_2^2) = (x_1x_2 + Ny_1y_2)^2 - N(x_1y_2 + x_2y_1)^2,</math> a form of what is now known as Brahmagupta's identity. Using this, he was able to "compose" triples <math>(x_1, y_1, k_1)</math> and <math>(x_2, y_2, k_2)</math> that were solutions of <math>x^2 - Ny^2 = k</math>, to generate the new triples
- <math>(x_1x_2 + Ny_1y_2 , x_1y_2 + x_2y_1 , k_1k_2)</math> and <math>(x_1x_2 - Ny_1y_2 , x_1y_2 - x_2y_1 , k_1k_2).</math>
Not only did this give a way to generate infinitely many solutions to <math>x^2 - Ny^2 = 1</math> starting with one solution, but also, by dividing such a composition by <math>k_1k_2</math>, integer or "nearly integer" solutions could often be obtained. For instance, for <math>N = 92</math>, Brahmagupta composed the triple (10, 1, 8) (since <math>10^2 - 92(1^2) = 8</math>) with itself to get the new triple (192, 20, 64). Dividing throughout by 64 ("8" for <math>x</math> and <math>y</math>) gave the triple (24, 5/2, 1), which when composed with itself gave the desired integer solution (1151, 120, 1). Brahmagupta solved many Pell's equations with this method, proving that it gives solutions starting from an integer solution of <math>x^2 - Ny^2 = k</math> for k = ±1, ±2, or ±4.<ref name=stillwell>Template:Citation.</ref>
The first general method for solving the Pell's equation (for all N) was given by Bhāskara II in 1150, extending the methods of Brahmagupta. Called the chakravala (cyclic) method, it starts by choosing two relatively prime integers <math>a</math> and <math>b</math>, then composing the triple <math>(a, b, k)</math> (that is, one which satisfies <math>a^2 - Nb^2 = k</math>) with the trivial triple <math>(m, 1, m^2 - N)</math> to get the triple <math>\big(am + Nb, a + bm, k(m^2 - N)\big)</math>, which can be scaled down to <math display="block">\left(\frac{am + Nb}{k}, \frac{a + bm}{k}, \frac{m^2 - N}{k}\right).</math>
When <math>m</math> is chosen so that <math>\frac{a + bm}{k}</math> is an integer, so are the other two numbers in the triple. Among such <math>m</math>, the method chooses one that minimizes <math>\frac{m^2 - N}{k}</math> and repeats the process. This method always terminates with a solution. Bhaskara used it to give the solution x = Template:Val, y = Template:Val to the N = 61 case.<ref name=stillwell/>
Several European mathematicians rediscovered how to solve Pell's equation in the 17th century. Pierre de Fermat found how to solve the equation and in a 1657 letter issued it as a challenge to English mathematicians.<ref>In February 1657, Pierre de Fermat wrote two letters about Pell's equation. One letter (in French) was addressed to Bernard Frénicle de Bessy, and the other (in Latin) was addressed to Kenelm Digby, whom it reached via Thomas White and then William Brouncker.
- Template:Cite book The letter to Frénicle appears on pp. 333–334; the letter to Digby, on pp. 334–335.
The letter in Latin to Digby is translated into French in:
Both letters are translated (in part) into English in:
- Template:Cite book</ref> In a letter to Kenelm Digby, Bernard Frénicle de Bessy said that Fermat found the smallest solution for N up to 150 and challenged John Wallis to solve the cases N = 151 or 313. Both Wallis and William Brouncker gave solutions to these problems, though Wallis suggests in a letter that the solution was due to Brouncker.<ref>In January 1658, at the end of {{#invoke:Lang|lang}} (letter 19), Wallis effusively congratulated Brouncker for his victory in a battle of wits against Fermat regarding the solution of Pell's equation. From p. 807 of (Wallis, 1693): "Et quidem cum Vir Nobilissimus, utut hac sibi suisque tam peculiaria putaverit, & altis impervia, (quippe non omnis fert omnia tellus) ut ab Anglis haud speraverit solutionem; profiteatur tamen qu'il sera pourtant ravi d'estre destrompé par cet ingenieux & scavant Signieur; erit cur & ipse tibi gratuletur. Me quod attinet, humillimas est quod rependam gratias, quod in Victoriae tuae partem advocare dignatus es, ..." (And indeed, Most Noble Sir [i.e., Viscount Brouncker], he [i.e., Fermat] might have thought [to have] all to himself such an esoteric [subject, i.e., Pell's equation] with its impenetrable profundities (for all land does not bear all things [i.e., not every nation can excel in everything]), so that he might hardly have expected a solution from the English; nevertheless, he avows that he will, however, be thrilled to be disabused by this ingenious and learned Lord [i.e., Brouncker]; it will be for that reason that he [i.e., Fermat] himself would congratulate you. Regarding myself, I requite with humble thanks your having deigned to call upon me to take part in your Victory, ...) Note: The date at the end of Wallis' letter is "Jan. 20, 1657"; however, that date was according to the old Julian calendar that Britain finally discarded in 1752: most of the rest of Europe would have regarded that date as January 31, 1658. See Old Style and New Style dates#Transposition of historical event dates and possible date conflicts.</ref>
John Pell's connection with the equation is that he revised Thomas Branker's translation<ref>Template:Citation.</ref> of Johann Rahn's 1659 book Teutsche Algebra<ref group=note>Teutsch is an obsolete form of Deutsch, meaning "German". Free E-book: Teutsche Algebra at Google Books.</ref> into English, with a discussion of Brouncker's solution of the equation. Leonhard Euler mistakenly thought that this solution was due to Pell, as a result of which he named the equation after Pell.<ref name=":1">Template:Cite book</ref>
The general theory of Pell's equation, based on continued fractions and algebraic manipulations with numbers of the form <math>P + Q\sqrt{a},</math> was developed by Lagrange in 1766–1769.<ref>"Solution d'un Problème d'Arithmétique", in Joseph Alfred Serret (ed.), Œuvres de Lagrange, vol. 1, pp. 671–731, 1867.</ref> In particular, Lagrange gave a proof that the Brouncker–Wallis algorithm always terminates.
SolutionsEdit
Fundamental solution via continued fractionsEdit
Let <math>h_i/k_i</math> denote the unique sequence of convergents of the regular continued fraction for <math>\sqrt{n}</math>. Then the pair of positive integers <math>(x_1, y_1)</math> solving Pell's equation and minimizing x satisfies x1 = hi and y1 = ki for some i. This pair is called the fundamental solution. The sequence of integers <math>[a_0; a_1,a_2,\ldots]</math> in the regular continued fraction of <math>\sqrt{n}</math> is always eventually periodic. It can be written in the form <math>\left[\lfloor\sqrt{n}\rfloor;\;\overline{a_1,a_2,\ldots,a_{r-1}, 2\lfloor\sqrt{n}\rfloor}\right]</math>, where <math>\lfloor\, \cdot\, \rfloor</math> denotes integer floor, and the sequence <math>a_1,a_2,\ldots,a_{r-1}, 2\lfloor\sqrt{n}\rfloor</math> repeats infinitely. Moreover, the tuple <math>(a_1,a_2,\ldots,a_{r-1})</math> is palindromic, the same left-to-right or right-to-left.<ref name="titu" />
The fundamental solution is <math display="block">(x_1, y_1)=\begin{cases} (h_{r-1}, k_{r-1}),&\text{ for }r\text{ even}\\ (h_{2r-1},k_{2r-1}),&\text{ for }r\text{ odd}\end{cases}</math>
The computation time for finding the fundamental solution using the continued fraction method, with the aid of the Schönhage–Strassen algorithm for fast integer multiplication, is within a logarithmic factor of the solution size, the number of digits in the pair <math>(x_1, y_1)</math>. However, this is not a polynomial-time algorithm because the number of digits in the solution may be as large as Template:Radic, far larger than a polynomial in the number of digits in the input value n.<ref name=":0">Template:Citation.</ref>
Additional solutions from the fundamental solutionEdit
Once the fundamental solution is found, all remaining solutions may be calculated algebraically from<ref name=":0" /> <math display="block">x_k + y_k \sqrt n = (x_1 + y_1 \sqrt n)^k,</math> expanding the right side, equating coefficients of <math>\sqrt{n}</math> on both sides, and equating the other terms on both sides. This yields the recurrence relations <math display="block">x_{k+1} = x_1 x_k + n y_1 y_k,</math> <math display="block">y_{k+1} = x_1 y_k + y_1 x_k.</math>
Concise representation and faster algorithmsEdit
Although writing out the fundamental solution (x1, y1) as a pair of binary numbers may require a large number of bits, it may in many cases be represented more compactly in the form <math display="block">x_1+y_1\sqrt n = \prod_{i=1}^t \left(a_i + b_i\sqrt n\right)^{c_i}</math> using much smaller integers ai, bi, and ci.
For instance, Archimedes' cattle problem is equivalent to the Pell equation <math>x^2 - 410\,286\,423\,278\,424\ y^2 = 1</math>, the fundamental solution of which has Template:Val digits if written out explicitly. However, the solution is also equal to <math display="block">x_1 + y_1 \sqrt n = u^{2329},</math> where <math display="block">u = x'_1 + y'_1 \sqrt{4\,729\,494} = (300\,426\,607\,914\,281\,713\,365\ \sqrt{609} + 84\,129\,507\,677\,858\,393\,258\ \sqrt{7766})^2</math> and <math>x'_1</math> and <math>y'_1</math> only have 45 and 41 decimal digits respectively.<ref name=":0" />
Methods related to the quadratic sieve approach for integer factorization may be used to collect relations between prime numbers in the number field generated by Template:Radic and to combine these relations to find a product representation of this type. The resulting algorithm for solving Pell's equation is more efficient than the continued fraction method, though it still takes more than polynomial time. Under the assumption of the generalized Riemann hypothesis, it can be shown to take time <math display="block">\exp O\left(\sqrt{\log N\cdot\log\log N}\right),</math> where N = log n is the input size, similarly to the quadratic sieve.<ref name=":0" />
Quantum algorithmsEdit
Hallgren showed that a quantum computer can find a product representation, as described above, for the solution to Pell's equation in polynomial time.<ref>Template:Citation.</ref> Hallgren's algorithm, which can be interpreted as an algorithm for finding the group of units of a real quadratic number field, was extended to more general fields by Schmidt and Völlmer.<ref>Template:Citation.</ref>
ExampleEdit
As an example, consider the instance of Pell's equation for n = 7; that is, <math display="block">x^2 - 7y^2 = 1.</math> The continued fraction of <math>\sqrt{7}</math> has the form <math>[2;\ \overline{1, 1, 1, 4}]</math>. Since the period has length <math>4</math>, which is an even number, the convergent producing the fundamental solution is obtained by truncating the continued fraction right before the end of the first occurrence of the period: <math>[2;\ 1,1,1]=\frac{8}{3}</math>.
The sequence of convergents for the square root of seven are
<math>h/k</math>
(convergent)<math>h^2 - 7 k^2</math>
(Pell-type approximation)<math>2 / 1</math> <math>-3</math> <math>3 / 1</math> <math>+2</math> <math>5 / 2</math> <math>-3</math> <math>8 / 3</math> <math>+1</math>
Applying the recurrence formula to this solution generates the infinite sequence of solutions
- (1, 0); (8, 3); (127, 48); (2024, 765); (32257, 12192); (514088, 194307); (8193151, 3096720); (130576328, 49353213); ... (sequence A001081 (x) and A001080 (y) in OEIS)
For the Pell's equation <math display="block">x^2 - 13y^2 = 1,</math> the continued fraction <math>\sqrt{13}=[3;\ \overline{1,1,1,1,6}]</math> has a period of odd length. For this the fundamental solution is obtained by truncating the continued fraction right before the second occurrence of the period <math>[3;\ 1,1,1,1,6,1,1,1,1]=\frac{649}{180}</math>. Thus, the fundamental solution is <math>(x_1, y_1)=(649, 180)</math>.
The smallest solution can be very large. For example, the smallest solution to <math>x^2 - 313y^2 = 1</math> is (Template:Val, Template:Val), and this is the equation which Frenicle challenged Wallis to solve.<ref>{{#invoke:citation/CS1|citation |CitationClass=web }}</ref> Values of n such that the smallest solution of <math>x^2 - ny^2 = 1</math> is greater than the smallest solution for any smaller value of n are
- 1, 2, 5, 10, 13, 29, 46, 53, 61, 109, 181, 277, 397, 409, 421, 541, 661, 1021, 1069, 1381, 1549, 1621, 2389, 3061, 3469, 4621, 4789, 4909, 5581, 6301, 6829, 8269, 8941, 9949, ... (sequence A033316 in the OEIS).
(For these records, see Template:Oeis for x and Template:Oeis for y.)
List of fundamental solutions of Pell's equationsEdit
The following is a list of the fundamental solution to <math>x^2 - n y^2 = 1</math> with n ≤ 128. When n is an integer square, there is no solution except for the trivial solution (1, 0). The values of x are sequence A002350 and those of y are sequence A002349 in OEIS.
| n | x | y |
|---|---|---|
| 1 | – | – |
| 2 | 3 | 2 |
| 3 | 2 | 1 |
| 4 | – | – |
| 5 | 9 | 4 |
| 6 | 5 | 2 |
| 7 | 8 | 3 |
| 8 | 3 | 1 |
| 9 | – | – |
| 10 | 19 | 6 |
| 11 | 10 | 3 |
| 12 | 7 | 2 |
| 13 | 649 | 180 |
| 14 | 15 | 4 |
| 15 | 4 | 1 |
| 16 | – | – |
| 17 | 33 | 8 |
| 18 | 17 | 4 |
| 19 | 170 | 39 |
| 20 | 9 | 2 |
| 21 | 55 | 12 |
| 22 | 197 | 42 |
| 23 | 24 | 5 |
| 24 | 5 | 1 |
| 25 | – | – |
| 26 | 51 | 10 |
| 27 | 26 | 5 |
| 28 | 127 | 24 |
| 29 | 9801 | 1820 |
| 30 | 11 | 2 |
| 31 | 1520 | 273 |
| 32 | 17 | 3 |
| n | x | y |
|---|---|---|
| 33 | 23 | 4 |
| 34 | 35 | 6 |
| 35 | 6 | 1 |
| 36 | – | – |
| 37 | 73 | 12 |
| 38 | 37 | 6 |
| 39 | 25 | 4 |
| 40 | 19 | 3 |
| 41 | 2049 | 320 |
| 42 | 13 | 2 |
| 43 | 3482 | 531 |
| 44 | 199 | 30 |
| 45 | 161 | 24 |
| 46 | 24335 | 3588 |
| 47 | 48 | 7 |
| 48 | 7 | 1 |
| 49 | – | – |
| 50 | 99 | 14 |
| 51 | 50 | 7 |
| 52 | 649 | 90 |
| 53 | 66249 | 9100 |
| 54 | 485 | 66 |
| 55 | 89 | 12 |
| 56 | 15 | 2 |
| 57 | 151 | 20 |
| 58 | 19603 | 2574 |
| 59 | 530 | 69 |
| 60 | 31 | 4 |
| 61 | 1766319049 | 226153980 |
| 62 | 63 | 8 |
| 63 | 8 | 1 |
| 64 | – | – |
| n | x | y |
|---|---|---|
| 65 | 129 | 16 |
| 66 | 65 | 8 |
| 67 | 48842 | 5967 |
| 68 | 33 | 4 |
| 69 | 7775 | 936 |
| 70 | 251 | 30 |
| 71 | 3480 | 413 |
| 72 | 17 | 2 |
| 73 | 2281249 | 267000 |
| 74 | 3699 | 430 |
| 75 | 26 | 3 |
| 76 | 57799 | 6630 |
| 77 | 351 | 40 |
| 78 | 53 | 6 |
| 79 | 80 | 9 |
| 80 | 9 | 1 |
| 81 | – | – |
| 82 | 163 | 18 |
| 83 | 82 | 9 |
| 84 | 55 | 6 |
| 85 | 285769 | 30996 |
| 86 | 10405 | 1122 |
| 87 | 28 | 3 |
| 88 | 197 | 21 |
| 89 | 500001 | 53000 |
| 90 | 19 | 2 |
| 91 | 1574 | 165 |
| 92 | 1151 | 120 |
| 93 | 12151 | 1260 |
| 94 | 2143295 | 221064 |
| 95 | 39 | 4 |
| 96 | 49 | 5 |
| n | x | y |
|---|---|---|
| 97 | 62809633 | 6377352 |
| 98 | 99 | 10 |
| 99 | 10 | 1 |
| 100 | – | – |
| 101 | 201 | 20 |
| 102 | 101 | 10 |
| 103 | 227528 | 22419 |
| 104 | 51 | 5 |
| 105 | 41 | 4 |
| 106 | 32080051 | 3115890 |
| 107 | 962 | 93 |
| 108 | 1351 | 130 |
| 109 | 158070671986249 | 15140424455100 |
| 110 | 21 | 2 |
| 111 | 295 | 28 |
| 112 | 127 | 12 |
| 113 | 1204353 | 113296 |
| 114 | 1025 | 96 |
| 115 | 1126 | 105 |
| 116 | 9801 | 910 |
| 117 | 649 | 60 |
| 118 | 306917 | 28254 |
| 119 | 120 | 11 |
| 120 | 11 | 1 |
| 121 | – | – |
| 122 | 243 | 22 |
| 123 | 122 | 11 |
| 124 | 4620799 | 414960 |
| 125 | 930249 | 83204 |
| 126 | 449 | 40 |
| 127 | 4730624 | 419775 |
| 128 | 577 | 51 |
ConnectionsEdit
Pell's equation has connections to several other important subjects in mathematics.
Algebraic number theoryEdit
Pell's equation is closely related to the theory of algebraic numbers, as the formula <math display="block">x^2 - n y^2 = (x + y\sqrt n)(x - y\sqrt n)</math> is the norm for the ring <math>\mathbb{Z}[\sqrt{n}]</math> and for the closely related quadratic field <math>\mathbb{Q}(\sqrt{n})</math>. Thus, a pair of integers <math>(x, y)</math> solves Pell's equation if and only if <math>x + y \sqrt{n}</math> is a unit with norm 1 in <math>\mathbb{Z}[\sqrt{n}]</math>.<ref>Template:Cite journal Ch. 7 The Pell Equation</ref> Dirichlet's unit theorem, that all units of <math>\mathbb{Z}[\sqrt{n}]</math> can be expressed as powers of a single fundamental unit (and multiplication by a sign), is an algebraic restatement of the fact that all solutions to the Pell's equation can be generated from the fundamental solution.<ref>{{#invoke:citation/CS1|citation |CitationClass=web }}</ref> The fundamental unit can in general be found by solving a Pell-like equation but it does not always correspond directly to the fundamental solution of Pell's equation itself, because the fundamental unit may have norm −1 rather than 1 and its coefficients may be half integers rather than integers.
Chebyshev polynomialsEdit
Demeyer mentions a connection between Pell's equation and the Chebyshev polynomials: If <math>T_i(x)</math> and <math>U_i(x)</math> are the Chebyshev polynomials of the first and second kind respectively, then these polynomials satisfy a form of Pell's equation in any polynomial ring <math>R[x]</math>, with <math>n = x^2 - 1</math>:<ref>Template:Citation.</ref> <math display="block">T_i^2 - (x^2-1) U_{i-1}^2 = 1.</math> Thus, these polynomials can be generated by the standard technique for Pell's equations of taking powers of a fundamental solution: <math display="block">T_i + U_{i-1} \sqrt{x^2-1} = (x + \sqrt{x^2-1})^i.</math> It may further be observed that if <math>(x_i, y_i)</math> are the solutions to any integer Pell's equation, then <math>x_i = T_i (x_1)</math> and <math>y_i = y_1 U_{i-1} (x_1)</math>.<ref>Template:Citation.</ref>
Continued fractionsEdit
A general development of solutions of Pell's equation <math>x^2 - n y^2 = 1</math> in terms of continued fractions of <math>\sqrt{n}</math> can be presented, as the solutions x and y are approximates to the square root of n and thus are a special case of continued fraction approximations for quadratic irrationals.<ref name="titu" />
The relationship to the continued fractions implies that the solutions to Pell's equation form a semigroup subset of the modular group. Thus, for example, if p and q satisfy Pell's equation, then <math display="block">\begin{pmatrix} p & q \\ nq & p \end{pmatrix}</math> is a matrix of unit determinant. Products of such matrices take exactly the same form, and thus all such products yield solutions to Pell's equation. This can be understood in part to arise from the fact that successive convergents of a continued fraction share the same property: If pk−1/qk−1 and pk/qk are two successive convergents of a continued fraction, then the matrix <math display="block">\begin{pmatrix} p_{k-1} & p_{k} \\ q_{k-1} & q_{k} \end{pmatrix}</math> has determinant (−1)k.
Smooth numbersEdit
Størmer's theorem applies Pell equations to find pairs of consecutive smooth numbers, positive integers whose prime factors are all smaller than a given value.<ref name="stormer">Template:Cite journal</ref><ref>Template:Cite journal</ref> As part of this theory, Størmer also investigated divisibility relations among solutions to Pell's equation; in particular, he showed that each solution other than the fundamental solution has a prime factor that does not divide n.<ref name=stormer/>
The negative Pell's equationEdit
The negative Pell's equation is given by <math display="block">x^2 - n y^2 = -1</math> and has also been extensively studied. It can be solved by the same method of continued fractions and has solutions if and only if the period of the continued fraction has odd length. A necessary (but not sufficient) condition for solvability is that n is not divisible by 4 or by a prime of form 4k + 3.<ref group=note>This is because the Pell equation implies that −1 is a quadratic residue modulo n.</ref> Thus, for example, x2 − 3 y2 = −1 is never solvable, but x2 − 5 y2 = −1 may be.<ref>Template:Cite journal</ref>
The first few numbers n for which x2 − n y2 = −1 is solvable are 1 (with only one trivial solution) and
- 2, 5, 10, 13, 17, 26, 29, 37, 41, 50, 53, 58, 61, 65, 73, 74, 82, 85, 89, 97, ... (sequence A031396 in the OEIS)
with infinitely many solutions. The solutions of the negative Pell's equation for <math>1 \le n \le 298</math> are:
| n | x | y |
|---|---|---|
| 1 | 0 | 1 |
| 2 | 1 | 1 |
| 5 | 2 | 1 |
| 10 | 3 | 1 |
| 13 | 18 | 5 |
| 17 | 4 | 1 |
| 26 | 5 | 1 |
| 29 | 70 | 13 |
| 37 | 6 | 1 |
| 41 | 32 | 5 |
| 50 | 7 | 1 |
| 53 | 182 | 25 |
| 58 | 99 | 13 |
| 61 | 29718 | 3805 |
| 65 | 8 | 1 |
| 73 | 1068 | 125 |
| 74 | 43 | 5 |
| 82 | 9 | 1 |
| n | x | y |
|---|---|---|
| 85 | 378 | 41 |
| 89 | 500 | 53 |
| 97 | 5604 | 569 |
| 101 | 10 | 1 |
| 106 | 4005 | 389 |
| 109 | 8890182 | 851525 |
| 113 | 776 | 73 |
| 122 | 11 | 1 |
| 125 | 682 | 61 |
| 130 | 57 | 5 |
| 137 | 1744 | 149 |
| 145 | 12 | 1 |
| 149 | 113582 | 9305 |
| 157 | 4832118 | 385645 |
| 170 | 13 | 1 |
| 173 | 1118 | 85 |
| 181 | 1111225770 | 82596761 |
| 185 | 68 | 5 |
| n | x | y |
|---|---|---|
| 193 | 1764132 | 126985 |
| 197 | 14 | 1 |
| 202 | 3141 | 221 |
| 218 | 251 | 17 |
| 226 | 15 | 1 |
| 229 | 1710 | 113 |
| 233 | 23156 | 1517 |
| 241 | 71011068 | 4574225 |
| 250 | 4443 | 281 |
| 257 | 16 | 1 |
| 265 | 6072 | 373 |
| 269 | 82 | 5 |
| 274 | 1407 | 85 |
| 277 | 8920484118 | 535979945 |
| 281 | 1063532 | 63445 |
| 290 | 17 | 1 |
| 293 | 2482 | 145 |
| 298 | 409557 | 23725 |
Let <math>\alpha = \Pi_{j\text{ is odd}} (1 - 2^j)</math>. The proportion of square-free n divisible by k primes of the form 4m + 1 for which the negative Pell's equation is solvable is at least α.<ref>Template:Citation.</ref> When the number of prime divisors is not fixed, the proportion is given by 1 − α.<ref>{{#invoke:citation/CS1|citation |CitationClass=web }}</ref><ref>Template:Cite arXiv</ref>
If the negative Pell's equation does have a solution for a particular n, its fundamental solution leads to the fundamental one for the positive case by squaring both sides of the defining equation: <math display="block">(x^2 - n y^2)^2 = (-1)^2</math> implies <math display="block">>(x^2 + n y^2)^2 - n(2xy)^2 = 1.</math>
As stated above, if the negative Pell's equation is solvable, a solution can be found using the method of continued fractions as in the positive Pell's equation. The recursion relation works slightly differently however. Since <math>(x + y\sqrt{n})(x - y\sqrt{n}) = -1</math>, the next solution is determined in terms of <math>i(x_k + y_k\sqrt{n}) = (i(x + y\sqrt{n}))^k</math> whenever there is a match, that is, when <math>k</math> is odd. The resulting recursion relation is (modulo a minus sign, which is immaterial due to the quadratic nature of the equation) <math display="block">x_k = x_{k-2} x_1^2 + n x_{k-2} y_1^2 + 2 n y_{k-2} y_1 x_1,</math> <math display="block">y_k = y_{k-2} x_1^2 + n y_{k-2} y_1^2 + 2 x_{k-2} y_1 x_1,</math> which gives an infinite tower of solutions to the negative Pell's equation (except for <math>n = 1</math>).
Generalized Pell's equationEdit
The equation <math display="block">x^2 - n y^2 = N</math> is called the generalized<ref name="Peker_2021">Template:Cite book</ref><ref name="Tamang_2022">Template:Cite report</ref> (or general<ref name="titu">Template:Cite book</ref>) Pell's equation. The equation <math>u^2 - n v^2 = 1</math> is the corresponding Pell's resolvent.<ref name="titu"/> A recursive algorithm was given by Lagrange in 1768 for solving the equation, reducing the problem to the case <math>|N| < \sqrt{n}</math>.<ref>Template:Cite book</ref><ref>{{#invoke:citation/CS1|citation |CitationClass=web }}</ref> Such solutions can be derived using the continued-fractions method as outlined above.
If <math>(x_0, y_0)</math> is a solution to <math> x^2 - n y^2 = N,</math> and <math>(u_k, v_k)</math> is a solution to <math>u^2 - n v^2 = 1,</math> then <math>(x_k, y_k)</math> such that <math>x_k + y_k \sqrt{n} = \big(x_0 + y_0 \sqrt{n}\big)\big(u_k + v_k \sqrt{n}\big)</math> is a solution to <math>x^2 - n y^2 = N</math>, a principle named the multiplicative principle.<ref name="titu"/> The solution <math>(x_k, y_k)</math> is called a Pell multiple of the solution <math>(x_0, y_0)</math>.
There exists a finite set of solutions to <math>x^2 - n y^2 = N</math> such that every solution is a Pell multiple of a solution from that set. In particular, if <math>(u, v)</math> is the fundamental solution to <math>u^2 - n v^2 = 1</math>, then each solution to the equation is a Pell multiple of a solution <math>(x, y)</math> with <math>|x| \le \tfrac{1}{2} \sqrt{|N|} \left(\sqrt{|U|} + 1\right)</math> and <math>|y| \le \tfrac{1}{2 \sqrt{n}} \sqrt{|N|} \left(\sqrt{|U|} + 1\right) </math>, where <math>U = u + v \sqrt n</math>.<ref name="kconrad">{{#invoke:citation/CS1|citation |CitationClass=web }}</ref>
If x and y are positive integer solutions to the Pell's equation with <math>|N| < \sqrt n</math>, then <math>x/y</math> is a convergent to the continued fraction of <math>\sqrt n</math>.<ref name="kconrad" />
Solutions to the generalized Pell's equation are used for solving certain Diophantine equations and units of certain rings,<ref>Template:Cite journal</ref><ref>Template:Cite journal</ref> and they arise in the study of SIC-POVMs in quantum information theory.<ref>Template:Cite journal</ref>
The equation <math display="block">x^2 - n y^2 = 4</math> is similar to the resolvent <math>x^2 - n y^2 = 1</math> in that if a minimal solution to <math>x^2 - n y^2 = 4</math> can be found, then all solutions of the equation can be generated in a similar manner to the case <math>N = 1</math>. For certain <math>n</math>, solutions to <math>x^2 - n y^2 = 1</math> can be generated from those with <math>x^2 - n y^2 = 4</math>, in that if <math>n \equiv 5 \pmod{8},</math> then every third solution to <math>x^2 - n y^2 = 4</math> has <math>x, y</math> even, generating a solution to <math>x^2 - n y^2 = 1</math>.<ref name="titu" />
NotesEdit
ReferencesEdit
<references/>
Further readingEdit
- Template:Cite book
- Template:Cite journal
- Template:Cite book
- Template:Cite book
- Template:Cite book
- Template:Cite book
External linksEdit
- Template:Mathworld
- Template:MacTutor
- Pell equation solver (n has no upper limit)
- Pell equation solver (n < 1010, can also return the solution to x2 − ny2 = ±1, ±2, ±3, and ±4)