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In mathematical physics, scalar potential describes the situation where the difference in the potential energies of an object in two different positions depends only on the positions, not upon the path taken by the object in traveling from one position to the other. It is a scalar field in three-space: a directionless value (scalar) that depends only on its location. A familiar example is potential energy due to gravity.

File:Electrodynamics vector calculus review gradient.svg
Vector field (right) and corresponding scalar potential (left).

A scalar potential is a fundamental concept in vector analysis and physics (the adjective scalar is frequently omitted if there is no danger of confusion with vector potential). The scalar potential is an example of a scalar field. Given a vector field Template:Math, the scalar potential Template:Mvar is defined such that: <ref>Template:Cite book</ref> <math display="block"> \mathbf{F} = -\nabla P = - \left( \frac{\partial P}{\partial x}, \frac{\partial P}{\partial y}, \frac{\partial P}{\partial z} \right), </math> where Template:Math is the gradient of Template:Mvar and the second part of the equation is minus the gradient for a function of the Cartesian coordinates Template:Mvar.Template:Efn In some cases, mathematicians may use a positive sign in front of the gradient to define the potential.<ref>See [1] for an example where the potential is defined without a negative. Other references such as Template:Citation avoid using the term potential when solving for a function from its gradient.</ref> Because of this definition of Template:Mvar in terms of the gradient, the direction of Template:Math at any point is the direction of the steepest decrease of Template:Mvar at that point, its magnitude is the rate of that decrease per unit length.

In order for Template:Math to be described in terms of a scalar potential only, any of the following equivalent statements have to be true:

  1. <math>-\int_a^b \mathbf{F}\cdot d\mathbf{l} = P(\mathbf{b})-P(\mathbf{a}),</math> where the integration is over a Jordan arc passing from location Template:Math to location Template:Math and Template:Math is Template:Mvar evaluated at location Template:Math.
  2. <math>\oint \mathbf{F}\cdot d\mathbf{l} = 0,</math> where the integral is over any simple closed path, otherwise known as a Jordan curve.
  3. <math>{\nabla}\times{\mathbf{F}} =0. </math>

The first of these conditions represents the fundamental theorem of the gradient and is true for any vector field that is a gradient of a differentiable single valued scalar field Template:Mvar. The second condition is a requirement of Template:Math so that it can be expressed as the gradient of a scalar function. The third condition re-expresses the second condition in terms of the curl of Template:Math using the fundamental theorem of the curl. A vector field Template:Math that satisfies these conditions is said to be irrotational (conservative).

File:Mass potential well increasing mass.gif
Gravitational potential well of an increasing mass where Template:Math

Scalar potentials play a prominent role in many areas of physics and engineering. The gravity potential is the scalar potential associated with the force of gravity per unit mass, or equivalently, the acceleration due to the field, as a function of position. The gravity potential is the gravitational potential energy per unit mass. In electrostatics the electric potential is the scalar potential associated with the electric field, i.e., with the electrostatic force per unit charge. The electric potential is in this case the electrostatic potential energy per unit charge. In fluid dynamics, irrotational lamellar fields have a scalar potential only in the special case when it is a Laplacian field. Certain aspects of the nuclear force can be described by a Yukawa potential. The potential play a prominent role in the Lagrangian and Hamiltonian formulations of classical mechanics. Further, the scalar potential is the fundamental quantity in quantum mechanics.

Not every vector field has a scalar potential. Those that do are called conservative, corresponding to the notion of conservative force in physics. Examples of non-conservative forces include frictional forces, magnetic forces, and in fluid mechanics a solenoidal field velocity field. By the Helmholtz decomposition theorem however, all vector fields can be describable in terms of a scalar potential and corresponding vector potential. In electrodynamics, the electromagnetic scalar and vector potentials are known together as the electromagnetic four-potential.

Integrability conditionsEdit

If Template:Math is a conservative vector field (also called irrotational, curl-free, or potential), and its components have continuous partial derivatives, the potential of Template:Math with respect to a reference point Template:Math is defined in terms of the line integral: <math display="block">V(\mathbf r) = -\int_C \mathbf{F}(\mathbf{r})\cdot\,d\mathbf{r} = -\int_a^b \mathbf{F}(\mathbf{r}(t))\cdot\mathbf{r}'(t)\,dt,</math> where Template:Mvar is a parametrized path from Template:Math to Template:Math, <math display="block">\mathbf{r}(t), a\leq t\leq b, \mathbf{r}(a)=\mathbf{r_0}, \mathbf{r}(b)=\mathbf{r}.</math>

The fact that the line integral depends on the path Template:Mvar only through its terminal points Template:Math and Template:Math is, in essence, the path independence property of a conservative vector field. The fundamental theorem of line integrals implies that if Template:Mvar is defined in this way, then Template:Math, so that Template:Mvar is a scalar potential of the conservative vector field Template:Math. Scalar potential is not determined by the vector field alone: indeed, the gradient of a function is unaffected if a constant is added to it. If Template:Mvar is defined in terms of the line integral, the ambiguity of Template:Mvar reflects the freedom in the choice of the reference point Template:Math.

Altitude as gravitational potential energyEdit

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File:Gravity field near earth.gif
uniform gravitational field near the Earth's surface
File:GravityPotential.jpg
Plot of a two-dimensional slice of the gravitational potential in and around a uniform spherical body. The inflection points of the cross-section are at the surface of the body.

An example is the (nearly) uniform gravitational field near the Earth's surface. It has a potential energy <math display="block"> U = m g h </math> where Template:Mvar is the gravitational potential energy and Template:Mvar is the height above the surface. This means that gravitational potential energy on a contour map is proportional to altitude. On a contour map, the two-dimensional negative gradient of the altitude is a two-dimensional vector field, whose vectors are always perpendicular to the contours and also perpendicular to the direction of gravity. But on the hilly region represented by the contour map, the three-dimensional negative gradient of Template:Mvar always points straight downwards in the direction of gravity; Template:Math. However, a ball rolling down a hill cannot move directly downwards due to the normal force of the hill's surface, which cancels out the component of gravity perpendicular to the hill's surface. The component of gravity that remains to move the ball is parallel to the surface: <math display="block"> \mathbf F_\mathrm{S} = - m g \ \sin \theta </math> where Template:Mvar is the angle of inclination, and the component of Template:Math perpendicular to gravity is <math display="block"> \mathbf F_\mathrm{P} = - m g \ \sin \theta \ \cos \theta = - {1 \over 2} m g \sin 2 \theta. </math> This force Template:Math, parallel to the ground, is greatest when Template:Mvar is 45 degrees.

Let Template:Math be the uniform interval of altitude between contours on the contour map, and let Template:Math be the distance between two contours. Then <math display="block"> \theta = \tan^{-1}\frac{\Delta h}{\Delta x} </math> so that <math display="block"> F_P = - m g { \Delta x \, \Delta h \over \Delta x^2 + \Delta h^2 }. </math> However, on a contour map, the gradient is inversely proportional to Template:Math, which is not similar to force Template:Math: altitude on a contour map is not exactly a two-dimensional potential field. The magnitudes of forces are different, but the directions of the forces are the same on a contour map as well as on the hilly region of the Earth's surface represented by the contour map.

Pressure as buoyant potentialEdit

In fluid mechanics, a fluid in equilibrium, but in the presence of a uniform gravitational field is permeated by a uniform buoyant force that cancels out the gravitational force: that is how the fluid maintains its equilibrium. This buoyant force is the negative gradient of pressure: <math display="block"> \mathbf{f_B} = - \nabla p. </math>

Since buoyant force points upwards, in the direction opposite to gravity, then pressure in the fluid increases downwards. Pressure in a static body of water increases proportionally to the depth below the surface of the water. The surfaces of constant pressure are planes parallel to the surface, which can be characterized as the plane of zero pressure.

If the liquid has a vertical vortex (whose axis of rotation is perpendicular to the surface), then the vortex causes a depression in the pressure field. The surface of the liquid inside the vortex is pulled downwards as are any surfaces of equal pressure, which still remain parallel to the liquids surface. The effect is strongest inside the vortex and decreases rapidly with the distance from the vortex axis.

The buoyant force due to a fluid on a solid object immersed and surrounded by that fluid can be obtained by integrating the negative pressure gradient along the surface of the object: <math display="block"> F_B = - \oint_S \nabla p \cdot \, d\mathbf{S}. </math>

Scalar potential in Euclidean spaceEdit

In 3-dimensional Euclidean space Template:Tmath, the scalar potential of an irrotational vector field Template:Math is given by <math display="block"> \Phi(\mathbf{r}) = \frac{1}{4\pi} \int_{\mathbb R^3} \frac{\operatorname{div} \mathbf{E}(\mathbf{r}')}{\left\| \mathbf{r} - \mathbf{r}' \right\|} \, dV(\mathbf r') </math> where Template:Math is an infinitesimal volume element with respect to Template:Math. Then <math display="block"> \mathbf{E} = -\mathbf{\nabla} \Phi = - \frac{1}{4\pi} \mathbf{\nabla} \int_{\mathbb R^3} \frac{\operatorname{div} \mathbf{E}(\mathbf{r}')}{\left\| \mathbf{r} - \mathbf{r}' \right\|} \, dV(\mathbf r') </math> This holds provided Template:Math is continuous and vanishes asymptotically to zero towards infinity, decaying faster than Template:Math and if the divergence of Template:Math likewise vanishes towards infinity, decaying faster than Template:Math.

Written another way, let <math display="block">\Gamma(\mathbf{r}) = \frac{1}{4\pi} \frac{1}{\|\mathbf r\|}</math> be the Newtonian potential. This is the fundamental solution of the Laplace equation, meaning that the Laplacian of Template:Math is equal to the negative of the Dirac delta function: <math display="block">\nabla^2\Gamma(\mathbf r) + \delta(\mathbf r) = 0.</math> Then the scalar potential is the divergence of the convolution of Template:Math with Template:Math: <math display="block">\Phi = \operatorname{div}(\mathbf E * \Gamma).</math>

Indeed, convolution of an irrotational vector field with a rotationally invariant potential is also irrotational. For an irrotational vector field Template:Math, it can be shown that <math display="block">\nabla^2\mathbf{G} = \mathbf{\nabla}(\mathbf{\nabla} \cdot{} \mathbf{G}).</math> Hence <math display="block">\nabla\operatorname{div}(\mathbf E * \Gamma) = \nabla^2(\mathbf E * \Gamma) = \mathbf E * \nabla^2\Gamma = -\mathbf E * \delta = -\mathbf E </math> as required.

More generally, the formula <math display="block">\Phi = \operatorname{div}(\mathbf E * \Gamma)</math> holds in Template:Mvar-dimensional Euclidean space (Template:Math) with the Newtonian potential given then by <math display="block">\Gamma(\mathbf r) = \frac{1}{n(n-2)\omega_n \|\mathbf r\|^{n-2}}</math> where Template:Mvar is the volume of the unit Template:Mvar-ball. The proof is identical. Alternatively, integration by parts (or, more rigorously, the properties of convolution) gives <math display="block">\Phi(\mathbf r) = -\frac{1}{n\omega_n} \int_{\mathbb R^n} \frac{\mathbf E(\mathbf r')\cdot (\mathbf r-\mathbf r')}{\|\mathbf r-\mathbf r'\|^n} \,dV(\mathbf r').</math>

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